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Gre4nikov [31]
3 years ago
7

Asap please !

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

2/3 I think I'm not completely sure

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Distance between two points (−5,−5) and (-9, -2)
sergey [27]

Answer: 5

Step-by-step explanation: d = √(x^²-x^₁)^2+(y^²-y^₁)^2 d = √ (-9--5)^2+ (-2 - -5)^2 d = √(-4)^2 + (3)^2 d = √16 + 9 d = √25 d = 5

8 0
3 years ago
Sometimes life is tricky.
skad [1K]

thanks for the message !!

3 0
2 years ago
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Please help! (Will mark brainlist!)
alexandr402 [8]

Answer:

0.285

Step-by-step explanation:

28.5/100 = 0.285

7 0
3 years ago
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A store finds that its sales revenue changes at a rate given by S'(t) = −30t2 + 420t dollars per day where t is the number of da
allochka39001 [22]

Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation S'(t)= -30t^{2} + 420t. The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\  S(t)= -10t^{3} +210t^{2} \\

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

Given\ S(t) = -10t^{3} + 210t^{2}

S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860

Total sales = S(7) - S(0)

= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

To get S(14);

S(14) = -10(14)^{3} + 210(14)^{2}\\S(14) = -27,440+41,160\\S(14) = 13,720

The total sales for the second week after campaign ends = 13,720 - 6,860

= $6,860

8 0
3 years ago
Which are vertical angles? Check all that apply. ∠EAB and ∠BAC ∠EAB and ∠CAD ∠CAD and ∠FAE ∠CAB and ∠DAE ∠DAC and ∠DAE
Anastaziya [24]

Answer:

<CAB and <DAE are vertical angles

<EAB and <CAD are vertical angles

Step-by-step explanation:

this is because they are formed by the prolongation of the sides of the other angles and are opposite to them on the other side of the vertex.

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