Answer:
B. Update the UEFI firmware
Explanation:
UEFI (Unified Extensible Firmware Interface) is a standard firmware interface for PCs. It is responsible for waking up the computer hardware components and ensure they are functioning properly.
The old processor was controlled by an older version of the UEFI but to run the new processor, you update the Firmware Interface to enable it communicate with the computer's hardware components.
Answer:
Algorithm explained below
Explanation:
Algorithm to check duplicate when list of element is sorted:
CheckDuplicate( Sorted list )
initialize count = 0
Repeat untill we reach on end of list :
if next is not end of list and current element is equal to next element
count = count+1
increase the pointer to next untill a different element is found
end CheckDuplicate
Worst Case Time Complexity will be O(n). Because there is only one iteration over the list will be performed.
Yes We have improved the worst case time complexity compared to previous question.
Actually after applying sorting all the similar element to will be next to each other.Then we will start iterating one by one from one side and check which is similar to next.If a different element will be find then we will check whether it's next is similar to it or not.
eg. 1 1 1 2 2 2 4 4 4 we can check duplicate in one iteration.
Answer:
import java.util.*;
public class NightOut
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
double cost;
double cost2;
double cost3;
double grandtotal;
System.out.println("How much did dinner cost?");
cost = input.nextDouble();
System.out.println("How much is mini-golf for one person?");
cost2 = input.nextDouble();
System.out.println("How much did dessert cost?");
cost3 = input.nextDouble();
grandtotal = cost + cost2 * 2 + cost3;
System.out.println("Dinner: " + cost);
System.out.println("mini-golf: " + cost2);
System.out.println("Dessert: " + cost3);
System.out.println("Grand Total: " + grandtotal);
}
}
Explanation:
Engineering is the application of knowledge and technology is the body of knowledge:)
Answer:
10
Explanation:
Pointer arithmetic is tricky. The address is incremented by the sizeof the pointed element. A short is 2 bytes.
So adding 10 adds 20 bytes to the starting address of arr[].
In the expression, you're adding 10-6 = 4 to the start of the array, so you're pointing at the fifth element, arr[4] which is 10.
