Answer:
Step-by-step explanation:
A(4;1) B(1;3)
●use distance formula (see photo^)
Area of the canvas: 96 = 2 · W² + 2 · W L,
where W is the width and L is the length of a back and a top side. Two square sides have area W².
2 W L = 96 - 2 W² /:2
W L = 48 - W²
L = ( 48 - W² ) / W.
The inside volume of the shelter:
V = L · W · W = L · W²
V = W² · ( 48 - W² ) / W ;
V = 48 W - W³
We have to find the derivative:
V ` = 48 - 3 W²
48 - 3 W² = 0 ( for V max. )
3 W² = 48
W² = 48 : 3
W² = 16; W = √16; W = 4 ft.
L = ( 48 - 16 ) / 4 = 32 / 4 = 8 ft.
Answer: The length of the shelter for which the volume inside is maximized is 8 ft.
Ok set the necklace as X and the bracelet as Y
X+Y=192
X=3Y
Plug in 3Y for X in the first equation
4y=192
Y=48$
Plug that into your second equation
X=3(48)
X=144$
