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gladu [14]
3 years ago
7

the radius of the base of a cylinder is 10 centimeters, and urs height is 20 centimeters. a cone is used to fill the cylinder wi

th water. the radius of the cone base is 5 centimeters, and it’s height is 10 centimeters the number of times one needs to use the completely fillies cone to completely fill the cylinder with water is
Mathematics
1 answer:
Furkat [3]3 years ago
7 0

Answer:

The answer is 24 times

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X + 2x - 7/4=1 - x/2 -x ayudaaaaa
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|x| - |-x| = 0

Step-by-step explanation:

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What is the sum of 5+2 or 2+5?<br> Why is the sum the same?
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Because of communicative properties, it won't matter what way you put it bevause it's still "2" and '5"
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13. Translate the following verbal phrase
Artyom0805 [142]

a) algebraic expression

\frac{3+x}{5}=10

b) Solve and find value of x

x=47

Step-by-step explanation:

We need to translate the following verbal phrase  into an algebraic equation

The quotient of three more than a  number and five is ten

Let the number be x

three more than a  number is written as: 3+x

Since quotient is 10 so,

The algebraic expression will be:

\frac{3+x}{5}=10

Now, <u>solving to find value of x</u>

\frac{3+x}{5}=10

Multiplying both sides by 5

\frac{3+x}{5}*5=10*5\\3+x=50

Now Subtract -3 from both sides

3+x-3=50-3\\x=47

So, value of x=47

Learn More:

  • You can find more info about translating verbal phrase  into an algebraic equation

                    brainly.com/question/1600376

                    brainly.com/question/1617787

  • For finding value of x, more info can be found at:

                     brainly.com/question/1616605

Keywords: verbal phrase, algebraic expression

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8 0
3 years ago
A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a
Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y  grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)  [as x+y=14]

\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\

\Rightarrow x =(25 \times 14)/32=10.9375 grams

and y = 14-x= 14-10.9375=3.0625 grams.

Hence, 10.9375 grams of 82% gold and 3.0625  grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y  grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\

\Rightarrow x =(50 \times 14)/57=12.28 grams

and y = 14-x= 14-12.28=1.72 grams.

Hence, 12.28 grams of 82% gold and 1.72  grams of 50% gold added to make 14 grams of 75% gold.

3 0
3 years ago
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