With scientific notation remember this rule; if the exponent is positive, move the decimal point that many places to the right. If it is negative move it that many places to the left. What that will do is make the number larger or smaller to the correct value.
So for example, if you had to solve 1.02 x 10^4 you would move the decimal four places to the right. So you would end up with 10200.
As another example if you had to solve 1.02 x 10^-2 you would move the decimal two places to the left. That would give you .0120.
So now we are onto your problem. 2.606 x 10^7.
You would move the decimal seven places to the right, because the exponent is positive, that will make your number larger(which would make more sense if you were adding populations, right?).
That would give you 26,060,000 people living in Texas.
From there simply add the two populations together and you will have your answer!
32, 7
0, - 1
20, 4
You just plug in the numbers and solve
Answer:
The answer is 2.25 that makes profit
Step-by-step explanation:
Answer:
Mizuki is here to help! The answer is D!
Step-by-step explanation:
Ok... So there are 24 students in the class and no other students in the class has the same name right? So the fraction should be 
since there are three madisons, which will be 0.125!
Since three people have the same name, everyone else gets less probability of getting called so the answer would be D.
Answer:
The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎
Step-by-step explanation:
For a reflection across the line y = -x, we have, (x, y) → (y, x)
Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x
The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)
Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'
Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎
