2 years ago

The triangles shown are congruent. Which of the following statements must be true? A. YZ = JG

1 answer:

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kotykmax [81]

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KiRa [710]

For $x\ \textgreater \ 0$ , $2^x\ \textless \ 3^x$ , all the more $2^x\ \textless \ 3^x+1$ , therefore no solution.

For $x=0$ , we have $2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2$ . Obviously that' false.

For $x\ \textless \ 0$ both $2^x$ and $3^x$ , where $2^x\ \textgreater \ 3^x$ , belong to the range $(0,1)$ , then $3^x+1$ belong to the range $(1,2)$ .
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So, the equation $2^x=3^x+1$ doesn't have a solution.

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A store sells used DVDs for 8$ each and used videotapes for $6 each. the function rule 8d+6v can be used to represent the total

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