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larisa [96]
3 years ago
8

The pattern below follows the rule, "starting with a value of 4, every

Mathematics
1 answer:
inna [77]3 years ago
8 0

Answer:

C

Step-by-step explanation:

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5 Practice
alekssr [168]

Answer:

Given - A rectangle of length 18 feet and wide 14 feet

To find - Area

Solution -

Area of rectangle = Length * Breadth

=

18 \times 14

252 square feet

3 0
3 years ago
Read 2 more answers
60 cans of soup are arranged to be displayed in 10 rows. Why does the fraction 10 over 60 not represent this situation? Explain.
mojhsa [17]

<u><em>Explanation</em></u>: The reason why is because when divide 10/60 it becomes a decimals and cans can't be decimals, but if you divide 60/10 then it will be 6 cans in each row.

4 0
3 years ago
For which value of x is the equation 3(x+2)+x=2x+16 true?
Arturiano [62]

Answer:

1) take the first part of the equation and work it by multiplying (x+2) by 3

3(x+2)+x

3x +6+x

2)put the answer you got into the question you were given

3x + 6+x =2x +16

3)group the x variables and the non x variables

3x +x -2x =16 -6

4) Now work the equation you have

3x+x-2x=16-6

4x-2x=16-6

2x=16-6

2x=10

5) you divide both sides by the x variable

2x=10

2x/2 =10/2

x=5

therefore x is 5

3 0
3 years ago
A directed line segment begins at F(-8, -2), ends at H(8, 6), and is divided in the ratio 8 to 2 by G. What are the coordinates
I am Lyosha [343]

Given:

A directed line segment begins at F(-8, -2), ends at H(8, 6), and is divided in the ratio 8 to 2 by G.

To find:

The coordinates of point G.

Solution:

Section formula: If a point divide a line segment with end points (x_1,y_1) and (x_2,y_2) in m:n, then the coordinates of that point are

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Point G divide the line segment FH in 8:2. Using section formula, we get

G=\left(\dfrac{8(8)+2(-8)}{8+2},\dfrac{8(6)+2(-2)}{8+2}\right)

G=\left(\dfrac{64-16}{10},\dfrac{48-4}{10}\right)

G=\left(\dfrac{48}{10},\dfrac{44}{10}\right)

G=\left(4.8,4.4\right)

Therefore, the coordinates of point G are (4.8, 4.4).

4 0
3 years ago
A picture is x+20 cm in width and 2x-10 cm in length. The frame is a
Jobisdone [24]

Answer:

A = 1100cm^2

Step by step Explanation:

given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.

If the width is equal to the length which I assume is true if the width is constant.

than x+30=2x, which means x = 30.

if this is true than 30(30)+200 = 1100cm^2

8 0
3 years ago
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