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2 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

In-s [12.5K]2 years ago

8 0

Answer:

C. 3⁶

Step-by-step explanation:

Exponents with the same base follow this exponential rule for division:

xᵃ/xᵇ = xᵃ⁻ᵇ

When the bases are the same, we can subtract the exponents.

The bases are the same in this problem: 3. Therefore, we can subtract the exponents from each other:

3⁸/3²
3⁸⁻²
3⁶

The final and correct answer is C. 3⁶.

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Use the quadratic formula to find the solutions for..<br> y = 2x^2 - 9x + 5.

Yakvenalex [24]

Answer: $x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}$

Step-by-step explanation:

$2x^2-9x+5$

a=2

b=-9

c=5

$x=\frac{-b\frac{+}{}\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-9)\frac{+}{}\sqrt{(-9)^2-4(2)(5)} }{2(2)}$

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2 years ago

For the function f(x) = 7/2x-16, what is the difference quotient for all nonzero values of h?

sergey [27]

Answer:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}$

Step-by-step explanation:

Given

$f(x) = \frac{7}{2}x - 16$

Required

The difference quotient for h

The difference quotient is calculated as:

$\frac{f(x + h) - f(x)}{ h}$

Calculate f(x + h)

$f(x) = \frac{7}{2}x - 16$

$f(x+h) = \frac{7}{2}(x+h) - 16$

$f(x+h) = \frac{7}{2}x+ \frac{7}{2}h- 16$

The numerator of $\frac{f(x + h) - f(x)}{ h}$ is:

$f(x + h) - f(x) = \frac{7}{2}x+ \frac{7}{2}h- 16 -(\frac{7}{2}x - 16)$

$f(x + h) - f(x) = \frac{7}{2}x+ \frac{7}{2}h- 16 -\frac{7}{2}x + 16$

Collect like terms

$f(x + h) - f(x) = \frac{7}{2}x -\frac{7}{2}x + \frac{7}{2}h- 16 + 16$

$f(x + h) - f(x) = \frac{7}{2}h$

So, we have:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h \div h$

Rewrite as:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h * \frac{1}{h}$

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}$

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2 years ago

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Westkost [7]

Answer:

Step-by-step explanation:

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3 years ago

William has a 26 -liter glass tank. First, he wants to put some marbles in it, all of the same volume. Then, he wants to fill th

madreJ [45]

Subtract the volume of the water from the volume of the tank to get the total volume of the marbles.

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