Answer:
The area of Ralph's dog pen is 2.05 times larger than the area of Ruth's dog pen.
Step-by-step explanation:
Given that the dog pen for Ruth's dog is 7 feet long and 6 / 1.3 feet wide, while her friend Ralph's dog pen is 14 feet long and 6 / 1.2 feet wide, to determine how many times larger is the area of Ralph's dog pen, the following calculation must be performed:
1/3 = 0.333
1/2 = 0.5
7 x 6.333 = X
44,333 = X
14 x 6.5 = X
91 = X
44,333 = 100
91 = X
91 x 100 / 44.333 = X
9,100 / 44,333 = X
205.26 = X
100 = 1
205.26 = X
205.26 / 100 = X
2.05 = X
Thus, the area of Ralph's dog pen is 2.05 times larger than the area of Ruth's dog pen.
r = - 18
multiply both sides by 3 to eliminate the fraction
3 × 6 = - r ⇒ 18 = - r ⇒ r = - 18
Answer:
a. true
b. true
c. True
Step-by-step explanation:
a. The domain of a relation includes all possible set of data that are the x-values. Therefore, the domain of the relationship given would be: {2, 3, 5, 6}.
a is True.
b. The range includes all corresponding y-values. Therefore,
Range would be {1 4, 5, 7}
b is Tire.
c. There's 5 on both range and domain.
c is hungry.
Answer:
-13
Step-by-step explanation:
f(-2) = 3(-2) - 7
f(-2) = -6 - 7
f(-2) = <u>-13</u>
Answer:
a) 34mi
b) 10mi
c) 44mi
d) by Calculating the amount of miles it would take John to go to school plus the amount of miles it would take Sara to go to school. Then add the sum of the amount of miles it took for both to go to school.
Step-by-step explanation:
a) explanation:





b) explanation:





c) explanation: we already have all the data from John's house to Sara's House.
John's House to Sara's House = John's House to School + Sara's House to School.
Sara's House to School (Question #1) = 34mi
John's House to School (Question #2) = 10mi
34(mi) + 10(mi) = 44(mi)
d) explanation: explanation is on the answer