PLZ help geometry proof. Will give Brainlyiest I’ve posted question 3 times so you can get triple the points
1 answer:
Answer:
The two column proof can be presented as follows;
Statement Reason
1. p║q Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9 Corresponding angles on parallel lines
3. ∠9 ≅ ∠11 Transitive property of equality
4. a║b Corresponding angles on parallel lines are congruent
Step-by-step explanation:
The statements in the two column proof can be explained as follows;
Statement Explanation
1. p║q Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9 Corresponding angles on parallel lines crossed by a common transversal are congruent
3. ∠9 ≅ ∠11 Transitive property of equality
Given that ∠1 ≅ ∠11 and we have that ∠1 ≅ ∠9, then we can transit the terms between the two expressions to get, ∠9 ≅ ∠11 which is the same as ∠11 ≅ ∠9
4. a║b Corresponding angles on parallel lines are congruent
Whereby we now have ∠9 which is formed by line a and the transversal line q, is congruent to ∠11 which is formed by line b and the common transversal line q, and both ∠9 and ∠11 occupy corresponding locations on lines a and b respectively which are crossed by the transversal, line q, then lines a and b are parallel to each other or a║b.
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