Answer:
The two column proof can be presented as follows;
Statement Reason
1. p║q Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9 Corresponding angles on parallel lines
3. ∠9 ≅ ∠11 Transitive property of equality
4. a║b Corresponding angles on parallel lines are congruent
Step-by-step explanation:
The statements in the two column proof can be explained as follows;
Statement Explanation
1. p║q Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9 Corresponding angles on parallel lines crossed by a common transversal are congruent
3. ∠9 ≅ ∠11 Transitive property of equality
Given that ∠1 ≅ ∠11 and we have that ∠1 ≅ ∠9, then we can transit the terms between the two expressions to get, ∠9 ≅ ∠11 which is the same as ∠11 ≅ ∠9
4. a║b Corresponding angles on parallel lines are congruent
Whereby we now have ∠9 which is formed by line a and the transversal line q, is congruent to ∠11 which is formed by line b and the common transversal line q, and both ∠9 and ∠11 occupy corresponding locations on lines a and b respectively which are crossed by the transversal, line q, then lines a and b are parallel to each other or a║b.
Answer:
Step-by-step explanation:
To polygons are said to be similar if all the corresponding angles of given polygons are equal.
In the given figure, it can be seen that in quadrilateral FSHB and quadrilateral KTWJ all the corresponding angles are equal.
∠F=∠K
∠S=∠T
∠H=∠W
∠B=∠J
Therefore, The given polygons are similar.
Hence,