Write an equation of the line through (-2, - 1) having slope 8/7?

Mathematics

1 answer:

Usimov [2.4K]3 years ago

6 0

Answer:

When slope and one point are known follow instructions on this page:

http://www.1728.org/distance.htm

Calculate "b" from this equation:

b = y -mx where "m" is the slope

We'll use the point given (-2, -1) for "x" and "y"

b = -1 -(8/7) * -2

b = -1 + 16/7

b = 9/7

then we enter "b" and the slope into this equation

y = 8/7x +9/7

y = 1.142857 x + 1.2857142857

Step-by-step explanation:

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Find the equation of an exponential function in the form y = ab^x, given the points (0, 3) and (2, 108/25). Please simplify your

lilavasa [31]

We have the equation:

$y=a\cdot b^x$

We know two points and we will use them to calculate the parameters a and b.

The point (0,3) will let us know a, as b^0=1.

$\begin{gathered} y=a\cdot b^x \\ 3=a\cdot b^0=a \\ a=3 \end{gathered}$

Now, we use the point (2, 108/25) to calcualte b:

$\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}$

Then, we can write the equation as: