Replace ... with ≥ or ≤ so that the derived inequality will be true for any value for x: x^2-16x+64 ... 0
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Let's start with the area of the square
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches
now we just subtract and our answer is
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches
now we just subtract and our answer is