Answer:
I. think it is12, 6, 2, 1
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as Hernando and Rachel's solution are not provided. So, I will just solve the question directly.
Given

Required
Factor

Group into 2
![2mp-6p+27-9m = [2mp-6p]+[27-9m]](https://tex.z-dn.net/?f=2mp-6p%2B27-9m%20%3D%20%5B2mp-6p%5D%2B%5B27-9m%5D)
Factor each group
![2mp-6p+27-9m = 2p[m-3]+9[3-m]](https://tex.z-dn.net/?f=2mp-6p%2B27-9m%20%3D%202p%5Bm-3%5D%2B9%5B3-m%5D)
Rewrite 3 - m as -(m-3)
So, we have:
![2mp-6p+27-9m = 2p[m-3]-9[m-3]](https://tex.z-dn.net/?f=2mp-6p%2B27-9m%20%3D%202p%5Bm-3%5D-9%5Bm-3%5D)
Factor out m - 3
![2mp-6p+27-9m = [2p-9][m-3]](https://tex.z-dn.net/?f=2mp-6p%2B27-9m%20%3D%20%5B2p-9%5D%5Bm-3%5D)
Answer:0 = 3x - 21
Step-by-step explanation:
From this given function we can take an
x
common from its expression
i.e
x
2
−
6
x
=
x
(
x
−
6
)
As we know that the product of two numbers is zero,when either one of them is zero
then in the above expression that we just factorised
the function can be zero when either
x
=
0
or when
x
=
6
i.e when
x
=
0
,
0
(
0
−
6
)
=
0
when
x
=
6
,
6
(
6
−
6
)
=
6
(
0
)
Finally, our prize of all that math, the zeroes of the function are
0
and
6
these numbers are called the zeroes of the function because when you put these values in
x
the function gives zero.
Answer:
-8x
Step-by-step explanation:
Subtract 6°x from -2x.