14. How long does it take to travel a distance of 672 km at a speed of 96
1 answer:
You might be interested in
Answer: the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa
Explanation:
The question requires us to calculate the pressure, in kPa, connsidering the following information:
<em>number of moles = n = 4.20mol</em>
<em>volume of gas = V = 15.0L</em>
<em>temperature of gas = T = 280.0 K</em>
We can use the equation of ideal gases to calculate the pressure of the gas, as shown by the rearranged equation below:
Since the volume was given in L and the question requires us to calculate the pressure in kPa, we can use R in units of L.Pa/K.mol:
<em>R = 8314.46 L.Pa/K.mol</em>
Applying the values given by the question to the rearranged equation above, we'll have:
Therefore, the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa.
Answer:
Option A, 931 Kg
Explanation:
As we know that weight is equal to the product of mass and acceleration due to gravity.
Thus,
m/s2
Substituting the given values in above equation, we get -
Kg
Hence, option A is correct
535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
<h3>What is an ideal gas equation?</h3>The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given:
⇒
1 mole of is formed from 1 mole of charcoal, that means 1 mole of
is formed from 12 g of charcoal.
1 lbs = 453.592 grams
6.75 lbs = 6.75 x 453.592 =3061.746g
So, formed from 3061.746g of charcoal is:
= x 3061.746g
=255.14 mol.
Now, at STP, the volume of 1 mol of gas =22.4 L
Volume of 255.14 mol of = 255.14 x 22.4 L
Volume of 255.14 mol of = 535.8 L
Hence, 535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
Learn more about the ideal gas here:
#SPJ1