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-Dominant- [34]
4 years ago
5

Ammonia is produced by the following reaction.

Chemistry
1 answer:
kati45 [8]4 years ago
4 0
The answer, as you appear to have guessed, is
A) 7.5 moles of hydrogen would be needed to consume the available hydrogen. 

The atomic mass of N2 is 2 x 14 = 28, so 70 grams is 2.5 moles. 
The ratio of N2 to H2 in the equation is 3 to 1, so 7.5 mol of hydrogen would be needed to consume the available nitrogen. 
7 grams of H2 is only about 3.5 moles. 
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Determine the molecular formula of a compound having the empirical formula C9H17O and a molar mass of 847.56g/mol.
Arlecino [84]
 The  molecular  formula of a compound  having  the empirical  formula  C9H17O  is calculated as below

(C9H17O)n =847.56

{(12 x9 + 1 x17 + 1 x16)}n= 847.56

147 n = 847.56
divide bot
h side by 147
n= 6

(C9H17O)6 therefore the molecular formula = C54H102O6
7 0
4 years ago
A gas balloon has a volume of 106.0 liters when the temperature is 25.0 °C and the pressure is 740.0 mm Hg. What will its volume
ipn [44]

Answer : The final volume of gas will be, 103.3 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 740.0 mmHg  = 98.4 kPa

Conversion used : (1 mmHg = 0.133 kPa)

P_2 = final pressure of gas = 99.3 kPa

V_1 = initial volume of gas = 106.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 25.0^oC=273+25.0=298K

T_2 = final temperature of gas = 20.0^oC=273+20.0=293K

Now put all the given values in the above equation, we get:

\frac{98.4kPa\times 106.0L}{298K}=\frac{99.3kPa\times V_2}{293K}

V_2=103.3L

Therefore, the final volume of gas will be, 103.3 L

8 0
4 years ago
Indicate which reactions are redox reactions. check all that apply. check all that apply. 2na(s)+cl2(g)→2nacl(s) cd(s)+pb2+(aq)→
3241004551 [841]

Redox reactions are those in which the oxidation numbers of the elements involved are changed.

Equation 1:

2Na(s) + Cl2(g) --> 2NaCl

 

The oxidation numbers of Na and Cl in the reactant side are both zero because they are in elemental form. In the product side, however, the oxidation numbers are +1 and -1, respectively. Hence, this is an example of redox reaction.

Equation 2:

Cd(s) + Pb+2(aq) --> Cd2+(aq) + Pb(s)

The oxidation numbers of Cd and Pb+2 in the reactant side are 0 and +2, respectively. They are, however, +2 and 0 in the product side. Hence, this is also a redox reaction.

Equation 3:

Pb(NO3)2(liq) + 2LiCl(aq) --> PbCl2(s) + 2LiNO3(aq)

The oxidation numbers of the involved ions (both cations and anions) are not changed. Hence, this is NOT an oxidation reaction.

Equation 4:

C(s) + O2(g) --> CO2(g)

 Just as the equation 1 and 2, the oxidation numbers of the reactants are not similar to those in the product. Hence, this is an example of oxidation reaction. 

6 0
3 years ago
Why are significant figures rules for calculations more important in science than in math class?
inysia [295]

Answer:

The importance of significant figures

As stated before, it is important within the science fields that you are not more precise or accurate than the least accurate or precise number. In science, it is generally agreed upon that the last number digit in any figure is filled with uncertainty.

Explanation:

4 0
3 years ago
What happens to the volume of a gas in a closed container if the temperature increases, but the pressure remains the same? Why?
labwork [276]

Answer:

Volume will goes to increase.

Explanation:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

So when the temperature goes to increase the volume of gas also increase. Higher temperature increase the kinetic energy and molecules move randomly every where in given space so volume increase.

Now we will put the suppose values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 4.5 L × 348 K / 298 k

V₂ = 1566 L.K / 298 K

V₂ = 5.3 L

Hence prove that volume increase by increasing the temperature.

3 0
3 years ago
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