Explanation:
Molecular mass:
Atomic masses:
N = 14g/mol H = 1g/mol S = 32g/mol O = 16g/mol Cl = 35.5g/mol
C = 12g/mol
NH₃ = 14 + 3(1) = 17g/mol
SO₂ = 32 + 2(16) = 64g/mol
Cl₂ = 2(35.5) = 71g/mol
N₂ = 14(2) = 28g/mol
CH₄ = 12 + (4 x 1) = 16g/mol
To solve this problem;
we need to derive an equation to find the molecular mass from the given densities on the table.
At STP;
Number of moles =
eqn (i)
Also;
Number of moles =
eqn (ii)
Now we can equate the two equations;
= ![\frac{mass}{molar mass}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D)
since density is known, we have to rewrite the relationship by making molar mass the subject of the expression:
Molar mass = ![\frac{mass x 22.4}{volume of gas}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%20x%2022.4%7D%7Bvolume%20of%20gas%7D)
we know that;
Density = ![\frac{mass }{volume }](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%20%7D%7Bvolume%20%7D)
Molar mass = density x 22.4
Now ;
Molar mass for 1.25g/L = 1.25 x 22.4 = 28g/mol; which is for N₂
Molar mass for 2.86g/L = 2.86 x 22.4 = 64.1g/mol; which is for SO₂
Molar mass for 0.714g/L = 0.714 x 22.4 = 16g/mol; which is for CH₄
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Answer:
22.2 g of MgF₂
Explanation:
We star from the reaction:
NaF → sodium fluoride
Mg → Magnesium
2NaF + Mg → MgF₂ + 2Na
2 moles of sodium fluoride react to 1 mol of Mg in order to produce 1 mol of magnesium fluoride and 2 moles of sodium.
We convert mass of the reactant to moles:
30 g . 1mol / 41.98 g = 0.715 mol
We assume that Mg is in excess
As ratio is 2:1, if we have 0.715 moles of NaF we may produce the half of moles, of MgF₂
0.715 mol /2 = 0.357 moles of MgF₂
We convert moles to mass: 0.357 mol . 62.30g /mol = 22.2 g
Answer:
Reversible chemical reaction favoring products.
Explanation:
Hello,
In this case, if we assume the following chemical reaction to be carried out:
![A \longleftrightarrow B](https://tex.z-dn.net/?f=A%20%5Clongleftrightarrow%20B)
We understand that it is under equilibrium conditions. In addition, based on the law of mass action, the present equilibrium constant is defined as:
![K_{eq}=\frac{[B]_{eq}}{[A]_{eq}}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BB%5D_%7Beq%7D%7D%7B%5BA%5D_%7Beq%7D%7D)
Now, if Keq is greater than 1, it means that the concentration of the product B is greater than that of the reactant A, therefore, even though it is a reversible chemical reaction, it is favoring the formation of B it means the product(s).
Best regards.
I think the element that has been correctly defined by Antoine Lavoisier would be the element oxygen. He is famous for the discovery of the importance of the molecule oxygen in the process of combustion. He is is the one who characterized and named the element oxygen and hydrogen. Also, showing how these atoms combine in order to form a water molecule in the combustion process. He is considered as the father of modern chemistry as he helped in organizing nomenclature of the chemical compounds. He also is responsible for laying the foundations of the famous law of conservation of mass.