Answer:
The answer to your question is letter B. 9
Explanation:
Unbalanced reaction
Al₂(SO₄)₃ + Ca(OH)₂ ⇒ Al(OH)₃ + CaSO₄
Reactants Elements Products
2 Al 1
3 S 1
14 O 7
1 Ca 1
2 H 3
Balanced reaction
Al₂(SO₄)₃ + 3Ca(OH)₂ ⇒ 2Al(OH)₃ + 3CaSO₄
Reactants Elements Products
2 Al 2
3 S 3
18 O 18
3 Ca 3
6 H 6
The sum of the coefficients is 1 + 3+ 2+ 3 = 9
Answer:
ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.
Explanation:
apparently colorless light, for example ordinary daylight. It contains all the wavelengths of the visible spectrum at equal intensity.
Answer : The value of rate of reaction is ![1.35\times 10^{-8}Ms^{-1}](https://tex.z-dn.net/?f=1.35%5Ctimes%2010%5E%7B-8%7DMs%5E%7B-1%7D)
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The given chemical equation is:
![2NO+O_2\rightarrow 2NO_2](https://tex.z-dn.net/?f=2NO%2BO_2%5Crightarrow%202NO_2)
Rate law expression for the reaction is:
![\text{Rate}=k[NO]^a[O_2]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5Ea%5BO_2%5D%5Eb)
As per question,
a = order with respect to
= 2
b = order with respect to
= 1
Thus, the rate law becomes:
![\text{Rate}=k[NO]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BO_2%5D%5E1)
Now, calculating the value of rate of reaction by using the rate law expression.
Given :
k = rate constant = ![9.87\times 10^3M^{-2}s^{-1}](https://tex.z-dn.net/?f=9.87%5Ctimes%2010%5E3M%5E%7B-2%7Ds%5E%7B-1%7D)
[NO] = concentration of NO = ![7.86\times 10^{-3}M](https://tex.z-dn.net/?f=7.86%5Ctimes%2010%5E%7B-3%7DM)
= concentration of
= ![2.21\times 10^{-3}M](https://tex.z-dn.net/?f=2.21%5Ctimes%2010%5E%7B-3%7DM)
Now put all the given values in the above expression, we get:
![\text{Rate}=(9.87\times 10^3M^{-2}s^{-1})\times (7.86\times 10^{-3}M)^2\times (2.21\times 10^{-3}M)^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3D%289.87%5Ctimes%2010%5E3M%5E%7B-2%7Ds%5E%7B-1%7D%29%5Ctimes%20%287.86%5Ctimes%2010%5E%7B-3%7DM%29%5E2%5Ctimes%20%282.21%5Ctimes%2010%5E%7B-3%7DM%29%5E1)
![\text{Rate}=1.35\times 10^{-8}Ms^{-1}](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3D1.35%5Ctimes%2010%5E%7B-8%7DMs%5E%7B-1%7D)
Hence, the value of rate of reaction is ![1.35\times 10^{-8}Ms^{-1}](https://tex.z-dn.net/?f=1.35%5Ctimes%2010%5E%7B-8%7DMs%5E%7B-1%7D)
Answer:
Carbon has a total of four bonded pairs of electrons around it.
Explanation:
Since there are four "lines" around the C (which stands for Carbon), we can conclude that Carbon has a total of four bonded pairs of electrons around it.