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Hatshy [7]
3 years ago
13

Indicate which reactions are redox reactions. check all that apply. check all that apply. 2na(s)+cl2(g)→2nacl(s) cd(s)+pb2+(aq)→

cd2+(aq)+pb(s) pb(no3)2(aq)+2licl(aq)→pbcl2(s)+2lino3(aq) c(s)+o2(g)→co2(g)
Chemistry
1 answer:
3241004551 [841]3 years ago
6 0

Redox reactions are those in which the oxidation numbers of the elements involved are changed.

Equation 1:

2Na(s) + Cl2(g) --> 2NaCl

 

The oxidation numbers of Na and Cl in the reactant side are both zero because they are in elemental form. In the product side, however, the oxidation numbers are +1 and -1, respectively. Hence, this is an example of redox reaction.

Equation 2:

Cd(s) + Pb+2(aq) --> Cd2+(aq) + Pb(s)

The oxidation numbers of Cd and Pb+2 in the reactant side are 0 and +2, respectively. They are, however, +2 and 0 in the product side. Hence, this is also a redox reaction.

Equation 3:

Pb(NO3)2(liq) + 2LiCl(aq) --> PbCl2(s) + 2LiNO3(aq)

The oxidation numbers of the involved ions (both cations and anions) are not changed. Hence, this is NOT an oxidation reaction.

Equation 4:

C(s) + O2(g) --> CO2(g)

 Just as the equation 1 and 2, the oxidation numbers of the reactants are not similar to those in the product. Hence, this is an example of oxidation reaction. 

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Gala2k [10]

Answer:

Alright the very first thing you need to do is balance the equation:

2HCl + Na2CO3 -----> 2NaCl + CO2 + H2O

Now we need to find the limiting reactant by converting the volume to moles of both HCl and Na2CO3.

Volume x Concentration/molarity = moles

0.235L x 0.6 M = 0.141 moles / molar ratio of 2 = 0.0705 moles of HCl

0.094L x 0.75 M = 0.0705 moles /molar ratio of 1  = 0.0705 moles of Na2CO3

Since both of the moles are equal, it means the entire reaction is complete (while the identification of limiting reactant may seem like an unnecessary step, it's quite essential in stoichiometry, so keep an eye out) and there is no excess of any reactant.

Now we know that the product we want to calculate is aqueous so, following the law of conservation of mass, we should add both volumes together to calculate how much volume we could get for NaCl.

0.235 + 0.094 = 0.329L of NaCl

Now we apply the C1V1 = C2V2 equation using the concentration and volume of Na2CO3 because it's molar ratio is one to one to NaCl (You can also use HCL, but you have to divide their moles by 2 for the molar ratio)  and the volume we just calculated for NaCl.

(0.75M) x (0.094L) = C2 x (0.329L)

Rearrange equation to solve for C2:

<u>(0.75M) x (0.094L)</u>  =  C2

    (0.329L)

C2 = 0.214 M (Rounded)

<u>When the reaction is finished, the NaCl solution will have a molarity concentration of 0.214 M.</u>

<u></u>

<u />

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Explanation:

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What elements would likely form an ionic bond?
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Answer:

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a. transferred

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Explanation:

Ionic bonds form between metals and non-metals when electrons are transferred from one specie to another.

  • The electrostatic attraction from the resulting ions forms the ionic bonds.
  • A metal is electropositive and will readily donate electrons
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Since Mg and Cl are the only metal - non-metal pair, and ionic bond will form between them.

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47 is the atomic number of the element Ag.

The atomic number is the number of protons in an atom. For a specie in neutral state, the number of protons and electrons are the same.

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