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Answer:
Newton's Second Law
Explanation:
Newton's second law basically states that the acceleration of a body which is produced by a net force is directly proportional to the magnitude of net force applied in the same direction.
This tells us that
F is directly proportional to a
⇒ F= ma
So we can also state from the above equation, that when we have more mass, we need more net force to accelerate it. Here, we are keeping the acceleration constant so we can surely say that force and mass varies directly.
Therefore, we have made good use of Newton's Second Law of motion to arrive at this conclusion.
Answer:
The hydrogen ion concentrations associated with these pH value 7.35 is 
The hydrogen ion concentrations associated with these pH value 7.45 is 
.
Explanation:
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
1) pH = 7.35
Putting values in above equation, we get:
![7.35=-\log[H^+]](https://tex.z-dn.net/?f=7.35%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=4.467\times 10^{-8} M\approx 4.5\times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D4.467%5Ctimes%2010%5E%7B-8%7D%20M%5Capprox%204.5%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentrations associated with these pH value 7.35 is
2) pH = 7.45
Putting values in above equation, we get:
![7.45=-\log[H^+]](https://tex.z-dn.net/?f=7.45%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=3.548\times 10^{-8}M \approx 3.6\times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D3.548%5Ctimes%2010%5E%7B-8%7DM%20%5Capprox%203.6%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentrations associated with these pH value 7.45 is .
Answer:
M = 0.050 M
Explanation:
WE have an acid base reaction between NaOH and HCl. The reaction is as follow:
HCl + NaOH -------> NaCl + H₂O
As we can see, we have a balanced equation already, and we can also see that the mole ratio between the HCl and NaOH is 1:1, therefore we can use the following expression:
M₁V₁ = M₂V₂ 1: acid; 2: base
This expression is used when the reactions has reached the equivalence point. As we want to know the concentration of the base, we just solve for M₂ above so:
M₂ = M₁V₁ / V₂
All we have to do now is replace the given values and solve for the concentration:
M₂ = 0.15 * 27 / 81
<h2>
M₂ = 0.050 M</h2><h2>
This is the concentration of the base</h2>
Answer:
3.49X10⁻¹⁷ J
Explanation:
The energy of an electron is given by the equation:
Where Z is the number of protons of the atom and n is the energy level of the electron. For Be, Z = 4.
When n tends to infinity (1/n²) tends to 0, and at this point, the electron has left the atom, so it has ionized.
The ionization energy then is the energy of the electron that left the atom less the energy of the electron in the energy level:
I.E = - (2.18x10⁻¹⁸)x4²x0 - (-(2.18x10⁻¹⁸)x4²x(1/1²))
I.E = 3.49X10⁻¹⁷ J
