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alexira [117]
3 years ago
6

What is the enclosure act

Chemistry
1 answer:
VashaNatasha [74]3 years ago
4 0
The Inclosure Acts, which use an old or formal spelling of the word now usually spelt "enclosure", cover enclosure of open fields and common land in England and Wales, creating legal property rights to land previously held in common.
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Emma constructed a simple motor. When connected correctly, the coil of copper wire spins. Which of the following best describes
faltersainse [42]

Answer:

ok first your in my class and second im stuck too

Explanation:

3 0
3 years ago
In the following compound (HCl) How many electrons are gained and lost by each atom?
Verizon [17]

Explanation:

In HCL, one positive atom is given to chlorine from hydrogen so that it can complete it's octate. chlorine take one electron from hydrogen.

In NaCl, Sodium takes one electron from chlorine to complete its orbit with eight electrons. Chlorine gives one electron to sodium.

8 0
3 years ago
How many protons, neutrons, and electrons are present in an atom of zinc, Zn, with a mass
postnew [5]
Location the element zinc (Zn) on the periodic table:
Group number : 12
Period number : 4
Block : d block
Element : Transition elements.
Part 2:
Protons in an atom of Zn: 30
Part 3:
Electrons in a Zn atom: 30
Part 4 :
Neutron in an atom of Zn: 35
5 0
3 years ago
Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri
lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

           CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)

Calculate the amount of CO_{2} dissolved as follows.

             CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}

It is given that K_{CO_{2}} = 0.032 M/atm and P_{CO_{2}} = 1.9 \times 10^{-4} atm.

Hence, [CO_{2}] will be calculated as follows.

           [CO_{2}] = K_{CO_{2}} \times P_{CO_{2}}          

                           = 0.032 M/atm \times 1.9 \times 10^{-4}atm

                           = 0.0608 \times 10^{-4}

or,                        = 0.608 \times 10^{-5}

It is given that K_{a} = 4.46 \times 10^{-7}

As,      K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}

          4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}  

               [H^{+}]^{2} = 2.71 \times 10^{-12}

                      [H^{+}] = 1.64 \times 10^{-6}

Since, we know that pH = -log [H^{+}]

So,                      pH = -log (1.64 \times 10^{-6})

                                 = 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

3 0
3 years ago
Question 2
sasho [114]
I’m pretty sure the answer would be

24.6078
Hopefully that helps
5 0
3 years ago
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