The question is as follows: What is the% m / m of a solution in which 22 g of solute are dissolved in 44 g of solvent?
Answer: The% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
Explanation:
Given: Mass of solute = 22 g
Mass of solvent = 44 g
The percentage m/m is calculated using the following formula.
Substitute the values into above formula as follows.
Thus, we can conclude that the% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
Looks like 3*.5 mol of N, or 1.5*.5 N2
<span>convert that to grams.</span>
Answer:
No.
Explanation:
The reason comes the <em>Law of Conservation of Mass</em>.
In an ordinary chemical reaction, <em>you cannot create or destroy atoms</em>.
So, you must have as many atoms at the beginning of a reaction (in the reactants) as at the end (in the products)
We use this principle to balance chemical equations.
For example, the equation for the formation of water from hydrogen and oxygen is
2H₂ + O₂ ⟶ 2H₂O
There are four atoms of H and two of O both before and after the reaction.
Pure air is a mixture of several gases that are invisible and odorless. Consists of 78% nitrogen, 21% oxygen, and less than 1% of argon, carbon dioxide.
When the products of a reaction are hotter than the reactants, an exothermic reaction is happening. An exothermic reaction is a reaction that releases energy to the surroundings. The energy released should be more than what is absorbed in order to maintain the reaction.
