According to Hatfield, which kind of love is about caring and intertwining your

Graph the given inequality.<br> y ≤ 4 – | x |

love history [14]

You'll get two X values because there is a modulus.

3 0

3 years ago

The data show the traveler spend- ing in billions of dollars for a recent year for a sample of the states. Find the range, varia

Svetllana [295]

Solution :

Given data :

20.1 33.5 21.7 58.4 23.2 110.8 30.9

24.0 74.8 60.0

n = 10

Range : Arranging from lowest to highest.

20.1, 21.7, 23.2, 24.0, 30.9, 33.5, 58.4, 60.0, 74.8, 110.8

Range = low highest value - lowest value

= 110.8 - 20.1

= 90.7

Mean = $\frac{\sum x}{n}$

$=\frac{20.1+21.7+23.2+24.0+30.9+33.5+58.4+60.0+74.8+110.8}{10}$

$=\frac{457.4}{10}$

$=45.74$

Sample standard deviation :

$S=\sqrt{\frac{1}{n-1}\sum(x-\mu)^2}$

$S=\sqrt{\frac{1}{10-1}(20.1-45.74)^2+(21.7-45.74)^2+(23.2-45.74)^2+(24.0-45.74)^2+(30.9-45)^2}$

$\sqrt{(33.5-45.74)^2+(58.4-45.74)^2+(60.0-45.74)^2+(74.8-45.74)^2+(110.8-45.74)^2}$

$S=\sqrt{\frac{1}{9}(657.4+577.9+508.0+472.6+220.2+149.8+160.2+203.3+844.4+4232.8)}$ $S=\sqrt{\frac{1}{9}(8026.96)}$

$S=\sqrt{891.88}$

S = 29.8644

Variance = $S^2$

$=(29.8644)^2$

= 891.8823

6 0

2 years ago

A cylinder has a radius of 12 m and a height of 8 m. What is the approximate surface area of the cylinder? Use 3.14 for π. Use y

____ [38]

Answer:

1507m²

Step-by-step explanation:

Given parameters:

Radius of cylinder = 12m

Height of cylinder = 8m

π = 3.14

Unknown:

Surface Area of cylinder = ?

Solution:

The surface area of any body is the sum of all the area that covers a body.

For a cylinder, the surface area is given as;

SA = 2πr² + 2πrh

Where SA = Surface Area

r = radius of cylinder

h = height of cylinder

Now input the parameters in the given equation and solve;

SA = (2 x 3.14 x 12²) + (2 x 3.14 x 12 x 8)

SA = 904.32‬ + 603.264‬

SA = 1507.584‬m² = 1507m²

4 0

2 years ago

Read 2 more answers

Suppose you roll a fair six-sided die. Then you roll a fair eight-sided die. Match each probability to its correct value.

Anna35 [415]

Answer:

A) matches $\frac{5}{48}$

B) matches $\frac{1}{12}$

C) matches $\frac{1}{4}$

D) matches $\frac{1}{8}$

E) matches $\frac{5}{16}$

Step-by-step explanation:

The sample space for the roll of six sided die and eight sided die:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (1,7), (1,8)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (2,7), (2,8)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (3,7), (3,8)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (4,7), (4,8)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (5,7), (5,8)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6), (6,7), (6,8)

Therefore, the total number of outcomes (Sample space) = 48

Probability $=\frac{Number Of Ways Event Can Occur}{Sample Space}$

A) The possible ways of obtaining both numbers are odd numbers and their product is greater than 10 are: (3,5), (3,7), (5,3), (5,5), (5,7)

Total number of possible ways = 5

Sample space = 48

The probability that both numbers are odd numbers and their product is greater than 10:

$=\frac{5}{48}$

B) The possible ways of obtaining second number is twice the first number are: (1,2), (2,4), (3,6), (4,8)

Total number of possible ways = 4

Sample space = 48

The probability that the second number is twice the first number:

$=\frac{4}{48}$ $=\frac{1}{12}$

C) The possible ways of getting numbers whose sum is a multiple of 4 are: (1,3), (1,7), (2,2), (2,6), (3,1), (3,5), (4,4), (4,8), (5,3), (5,7), (6,2), (6,6)

Total number of possible ways = 12

Sample space = 48

The probability of getting numbers whose sum is a multiple of 4:

$=\frac{12}{48}$ $=\frac{1}{4}$

D) The possible ways of getting the sum of the two numbers is greater than 11 are: (4,8), (5,7), (5,8), (6,6), (6,7), (6,8)

Total number of possible ways = 6

Sample space = 48

the probability that the sum of the two numbers is greater than 11:

$=\frac{6}{48}$ $=\frac{1}{8}$

E) The possible ways of getting the second number rolled is less than the first number are: (1,2), (1,3), (1,4), (1,5), (1,6), (2,3), (2,4), (2,5), (2,6), (3,4), (3,5), (3,6), (4,5), (4,6), (5,6)

Total number of possible ways = 15

Sample space = 48

The probability that the second number rolled is less than the first number:

$=\frac{15}{48}$ $=\frac{5}{16}$

5 0

2 years ago

A chocolatier is creating chocolate truffles in the shape spheres. The truffles will be solid chocolate and have a radius of 2.5

Flauer [41]

Answer: Volume: 65.4 Weight: 46.4

Step-by-step explanation:

3 0

2 years ago