Answer:
2.86L
Explanation:
Given parameters:
V1 = 2.1L
T1 = 200°C = 200 + 273 = 473K
T 2 = 370°C = 370 + 273 = 643K
Unknown:
V2 = ?
Solution:
Since pressure is constant, we apply the Charles's law;
=
V is volume
T is the temperature
1 is the initial state
2 is the new state
=
V2 = 2.86L
The original concentration is 5.1 × 10⁹ CFU / ml
In order to attain a countable plate, the number of CFU must be present in between 10 and 200 per ml.
Let us take 0.1 ml and dilute it to 1 ml.
This minimizes the concentration to 5.1 × 10⁹ × 10⁻¹ = 5.1 × 10⁸ CFU/ml
In order to minimize the concentration in between 10 and 200, it can be reduced to 5.1 × 10¹
The final concentration = 5.1 × 10¹ CFU/ml
Initial concentration = 5.1 × 10⁹ CFU/ml
Volume of sample with 5.1 × 10¹ CFU = 5.1 × 10¹ CFU × (1 ml / 5.1 × 10⁹ CFU)
= 1.0 × 10⁻⁸ ml
This is the volume to be taken to obtain countable value, 51 CFU.
Answer:
1. B, D,
2.A, F
Explanation:
1. According to the law of conservation of mass, In a course of chemical reaction, matter can neither be created nor destroyed but can be changed from one form to another. This means the amount of matter at the begining and ending of a reaction must be thesame.
2. Chemical reaction is not easily reversible. when gas is produced, provided the reaction system is an open system, the gas cannot be recovered and the reactants cannot be recovered from the products. likewise color change are attributed to chemical reaction
Answer:
C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O
2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O
Explanation:
The reaction above is simply termed combustion reaction in which an organic compound react with oxygen to produce carbon dioxide and water. Thus, we can obtain the balanced equation for the reaction reaction as follow:
C₈H₁₈ + O₂ —> CO₂ + H₂O
There are 8 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 8 before CO₂ as shown below:
C₈H₁₈ + O₂ —> 8CO₂ + H₂O
There are 18 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 9 before H₂O as shown below:
C₈H₁₈ + O₂ —> 8CO₂ + 9H₂O
There are 2 atoms of O on the left side and a total of 25 atoms on the right side. It can be balance by writing 25/2 before O₂ as shown below:
C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O
Thus, the equation is balanced!
The above equation can also be written as follow:
C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O
Multiply through by 2
2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O
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