Question

A mass of water at 100°c is added to another mass Q of water at a temperature T and the resulting temperature is theta. Describe an expression for theta in terms of the quantities (specific heat capacity of water is 4.2JKg-¹K-¹).​

Answer 1

Answer:

Use the formula Where 1. q = Heat Energy 2. m = Mass 3. c = Specific Heat 4. ΔT = Change in temperature. 14640 J = (300 g)(2.44 J/g·°C)ΔT Solve for ΔT: 1. ΔT = 14640 J/(300 g)(2.44 J/g·°C) 2. ΔT = 20 °C 3. ΔT = Tfinal - Tinitial 4. Tfinal = Tinital+ ΔT 5. Tfinal= 10 °C + 20 °C 6. Tfinal= 30 °C Answer:The final temperature of the ethanol is 30 °C.

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