Hi there!
The answer is:

Let the input be represented by X. We can see we have to multiply it by -3/4, so we get -3/4X. To find our outcome (which is represented by y), we only have to add 2 to the function.
y (outcome) = - 3/4x (income) + 2
Answer:
D 7
Step-by-step explanation:
Total no. of bulb= 5
no. of defected bulb= 3
no. of not defected bulb=2
Total no. of bulb combination = 5C2
=5!/2!(5-2)!
= 5!/2!3!
= 5×4×3×2×1/2×1×3×2×1
=120/12
=10
( since a room can be lighted with one bulb also)
total no. of bulb combination when room shall not light = 3C2
3!/2!(3-2)!
= 3!/2! 1!
= 3×2×1/2×1×1
= 6/2
=3
Now,
Total no. of trial when room shall light
=10-3
=7
Hence, number of trial when the room shall be lighted is 7 which is option d
Answer:
f(x)
Step-by-step explanation:
f(x)=x-1/x+5
y=x-1/x+5
xy+5y=x-1
xy-x=-1-5y
x(y-1)=1-5y
x=-1-5y/y-1
x=-5
To answer this,f ind the cube root of 216: It is 6.
The dimensions of the cube are 6 by 6 by 6.