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Usimov [2.4K]
2 years ago
10

Jill is in Math Club. There are 20 students in the club. The sponsor will pick two students at random to run the meeting. What i

s the Probability that Jill will not be picked? Give answer as a decimal.
Mathematics
2 answers:
Diano4ka-milaya [45]2 years ago
7 0
In total there are 20 students and 2 students will be picked.

So far, you have \frac{2}{20}.

You can simplify that to \frac{1}{10}.

To turn that into a decimal, divide 1÷10. You will get 0.1 


BartSMP [9]2 years ago
3 0
Jill is one of the 18 students out of 20 students in the club that will not be picked.

18/20 = 0.9

The probability that Jill will not be picked is a 0.9 chance (90%).<span />
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Please help, im seriously stuck on this
Rasek [7]

Answer:

x=64

Step-by-step explanation:

the shapes are similar

since the difference between 20 and 24 is 4

then you add 4 to 60 and get 64

I don't actually know 100% that this is correct but it makes sense in my head

7 0
3 years ago
Please help I've been trying so many times
Annette [7]

Answer:

A. -2, 1

Step-by-step explanation:

Observe the chart and see where the f(x) and g(x) intersect.

When x=-2, f(-2)=g=(-2) and when x=1, f(1)=g=(1).

7 0
3 years ago
What is a word problem for 2/3 divides by 3/4
victus00 [196]
Ned thought he needed 2/3 cups of flour for his donut recipe, but in order for him to get the correct amount, he needs to divide by 3/4.
4 0
3 years ago
If the area of a square plot of<br> land is 9 miles squared, what is<br> the perimeter of this land?
tatyana61 [14]

Answer:

\huge{ \fbox{ \sf{12 \: miles}}}

Step-by-step explanation:

Given,

Area of a square plot = 9 miles

<u>First</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>land</u>

\boxed{ \sf{Area \: of \: a \: square \:  =  \:  {length}^{2} }}

\mapsto{ \sf{9 =  {length}^{2} }}

\mapsto{ \sf{ {length}^{2}  = 9}}

\mapsto{ \sf{ \sqrt{ {(length)}^{2} }} =  \sqrt{9} }

\mapsto{ \sf{length = 3 \: miles}}

<u>Now</u><u> </u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>perimeter</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>land</u> :

\boxed{ \sf{perimeter \: of \: a \: square = 4 \: * length}}

\mapsto{ \sf{perimeter \:  =  \: 4 \:  * \: 3}}

\mapsto{ \sf{perimeter \:  = 12 \: miles}}

The perimeter of the land = 12 miles

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

3 0
3 years ago
In a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer
stira [4]

Answer:

We conclude that 80% of patients stop smoking when given sustained care.

Step-by-step explanation:

We are given that in a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer smoking after one month.

Let p = <u><em>percentage of patients stop smoking when given sustained care.</em></u>

So, Null Hypothesis, H_0 : p = 80%     {means that 80% of patients stop smoking when given sustained care}

Alternate Hypothesis, H_A : p \neq 80%     {means that different from 80% of patients stop smoking when given sustained care}

The test statistics that would be used here <u>One-sample z test for proportions</u>;

                        T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of patients who stop smoking when given sustained care = 80.2%

           n = sample of patients = 192

So, <u><em>the test statistics</em></u>  =  \frac{0.802-0.80}{\sqrt{\frac{0.802(1-0.802)}{192} } }

                                     =  0.07

The value of z test statistics is 0.07.

<u></u>

<u>Also, P-value of the test statistics is given by the following formula;</u>

                P-value = P(Z > 0.07) = 1 - P(Z \leq 0.07)

                              = 1 - 0.52790 = 0.4721

<u>Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that 80% of patients stop smoking when given sustained care.

8 0
3 years ago
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