Answer:
The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.
Step-by-step explanation:
Let <em>X</em> = number of students who have laptops.
The probability of a student having a laptop is, P (X) = <em>p</em> = 0.37.
A random sample of <em>n</em> = 30 students is selected.
The event of a student having a laptop is independent of the other students.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The mean and standard deviation of a binomial random variable <em>X</em> are:

Compute the mean of the random variable <em>X</em> as follows:

The mean of the random variable <em>X</em> is 1.11.
Compute the standard deviation of the random variable <em>X</em> as follows:

The standard deviation of the random variable <em>X</em> is 0.836.
Answer:
True
Step-by-step explanation:
0 . 0 0 0
whole Tenths Hundredths Thousandths
Answer:
Step-by-step explanation:

Answer:
2 1/3 times as far
Step-by-step explanation:
The ratio of distances is ...
(Monday distance) / (Tuesday distance) = (6 2/9)/(2 2/3)
= (56/9)/(8/3) = (56·3)/(8·9) = 7/3 = 2 1/3
They hiked 2 1/3 times as far on Monday as they did on Tuesday.