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3 years ago

Please help me with this review question.

Physics

1 answer:

jolli1 [7]3 years ago

8 0

Answer:

28.7%

Explanation:

efficiency = work output /work input × 100

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A hockey puck with a mass of 0.18 kg is at rest on the horizontal frictionless surface of the rink. A player applies a horizonta

Leya [2.2K]

Hello!

$\large\boxed{0.018 N}$

Begin by finding the acceleration of the puck. Use the kinematic equation:

$d = v_{i} + \frac{1}{2}at^{2}$

The initial velocity is 0 m/s since the object was at rest, so we can rewrite the equation as:

$d = \frac{1}{2}at^{2}$

Plug in the given distance and time:

$1.25 = \frac{1}{2}a(5^{2})\\\\2.50 = 25a\\\\a = 0.1 m/s^{2}$

Find the net force using the formula F = m · a (Newton's Second Law)

F = 0.18 · 0.1

F = 0.018 N

6 0

3 years ago

We can change a gas to liquid by the temperature and the pressure.

hodyreva [135]

I am not sure how you want me to answer this, but yes, gas can go from being a gas to a liquid when the right temp and pressure is applied.

6 0

4 years ago

Need help with this question

lakkis [162]

Answer:

1.39m

Explanation:

5 0

2 years ago

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A space probe is orbiting a planet on a circular orbit of radius R and a speed v. The acceleration of the probe is a. Suppose ro

Mamont248 [21]

Answer:

acceleration in the new orbit is 8 time of acceleration of planet in old orbit

$a_{new} = 8a.$

Explanation:

given data:

radius of orbit = R

Speed pf planet = v

new radius = 0.5R

new speed = 2v

we know that acce;ration is given as

$a = \frac{v^{2}}{R},$

$a_{new} =\frac{(2v)^{2}}{0.5R},$

$= \frac{4v^{2}}{0.5R}$

$= \frac{8 v^{2}}{R}$

$a_{new} = 8a.$

acceleration in the new orbit is 8 time of acceleration of planet in old orbit

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4 years ago

QUICK!! What class of leer is shown below?

wlad13 [49]

Answer:

3rd class lever

HOPE IT HELPS YOU OUT PLEASE MARK IT AS BRAINLIEST AND FOLLOW ME PROMISE YOU TO FOLLOW BACK ON BRAINLY.IN

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3 years ago

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