An elliptical galaxy is a type of galaxy having an approximately ellipsoidal shape and a smooth, nearly featureless brightness profile.
Unlike flat spiral galaxies with organization and structure, they are more three-dimensional, without much structure, and their stars are in somewhat random orbits around the center.
Answer
given,
SAT is 500 with a standard deviation of 100.
a sample of 400 students whose family income was between $70,000 and $80,000 had an average verbal SAT score of 511.
sample mean =
=
= 5
95% confidence level is achieved within +/- 1.960 standard deviations.
1.960 standard deviations x 5 is equal to +/- 9.8
confidence interval = 511 - 9.8 --- 511 + 9.8
= 501.2-----520.8
A bowling ball of 7.0 kg will be weighed around 15.54 lbs (pounds) at the surface of the Earth.
<u>Explanation:</u>
The weight of the bowling ball as given in the question,
Since we know that the force of gravity acting on an object at the surface of the Earth is 2.22 lb i.e. the object will be weighed as 2.22 lb at the surface of the Earth. Similarly, here in this case;
The weight of the bowling ball,
Hence, the bowling ball will be weighed as 15.54 lbs at the surface of the Earth.
I'd just keep in mind the relationships for: g = 9.81 m/s²
<span>and universal gravitational acceleration: </span>
<span>ie that: </span>
<span>for MASS, its directly proportional: </span>
<span>a mass that is 0.815 of Earth's would have a gravitational acceleration that's: </span>
<span>0.815g </span>
<span>and </span>
<span>for RADIUS (R) of planet, it's inversely proportional to the square of R </span>
<span>a planet with radius that's 0.949 of Earth's would have a gravitational acceleration of: </span>
<span>(1/0.949)² = 1.11g </span>
<span>the combination of these two effects would be: </span>
<span>(0.815 • 1.11)g = 0.905g = 8.88 m/s²</span>