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3 years ago

2 Physic Questions For 20 Points ✨

1 answer:

8 0

Jupiter Cannot Become A Star.
Jupiter Is The Fastest Spinning Planet In The Solar System.
The Clouds On Jupiter Are Only 50 km Thick.

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Determine the 3 standing waves for a 4 m length of rope.

strojnjashka [21]

Harmonics, Loop and Harmonic number

Hope this helps :)

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3 years ago

I don’t know if I did these rights someone check them or give me the answers? I know the photo has some stuff cut off but you ca

Nana76 [90]

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3 years ago

Define SI unit of force. A force of 8N acting on a body changes its velocity uniformly from 2 m/s to 5 m/s in 20s. Calculate

laila [671]

Answer:

si unit of force is Newton or dyne

6 0

1 year ago

A helium balloon is filled to a volume of 2.88 x 103 L at 722 mm Hg and 19Â°C. When the balloon is released, it rises to an alti

inn [45]

Answer:

V₂=4.57 x 10³ L

Explanation:

Given that

V₁= 2.88 x 10³ L

P₁=722 mm Hg

T₁ = 19°C

T₁ =292 K

P₂=339 mm Hg

T₂= - 55°C

T₂=218 K

Lets take final volume = V₂

We know that ideal gas equation

PV = m R T

By applying mass conservation

$\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}$

$\dfrac{722\times 2.88\times 10^3}{292}=\dfrac{339\times V_2}{218}$

V₂=4.57 x 10³ L

Therefore volume will be 4.57 x 10³ L

3 0

3 years ago

A ball is thrown vertically upward with a speed of 18.0 m/s. (a) How high does it rise? (b) How long does it take to reach its h

Mrrafil [7]

Answer:

a) $y=16.53m$

b) $t_{up}=1.83s$

c) $t_{down}=1.84s$

d) $v=-18m/s$

Explanation:

a) To find the highest point of the ball we need to know that at that point the ball stops going up and its velocity become 0

$v^{2} =v^{2} _{o} +2g(y-y_{o})$

$0=(18)^{2} -2(9.8)(y-0)$

Solving for y

$y=\frac{(18)^{2} }{2(9.8)}=16.53m$

b) To find how long does it take to reach that point:

$v=v_{o}+at$

$0=18-9.8t$

Solving for t

$t_{up} =\frac{18m/s}{9.8m/s^{2} }= 1.83s$

c) To find how long does it take to hit the ground after it reaches its highest point we need to find how long does it take to do the whole motion and then subtract the time that takes to go up

$y=y_{o}+v_{o}t+\frac{1}{2}gt^{2}$

$0=0+18t-\frac{1}{2}(9.8)t^{2}$

Solving for t

$t=0 s$ or $t=3.67s$

Since time can not be negative, we choose the second option

$t_{down}=t-t_{up}=3.67s-1.83s=1.84s$

d) To find the velocity when it returns to the level from which it started we need to use the following formula:

$v=v_{o}+at$

$v=18m/s-(9.8m/s^{2} )(3.67s)=-18m/s$

The sign means the ball is going down

8 0

4 years ago