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10 months ago

The conservation of momentum is most closely related to Newton's?

Physics

1 answer:

AleksandrR [38]10 months ago

3 0

The conservation of momentum is most closely related to Newton's third law.

According to the conservation of momentum, momentum is neither created nor destroyed, although it can change from one form to another.

According to Newton's third law, for every action, there is an opposite reaction, and energy is neither created nor destroyed. Rather the energy is changed from the action to the reaction in a given system and the amount of energy remains the same.

Both the conservation of momentum and Newton's third law imply that energy in a system can be converted but the value remains the same in a system and hence is closely related.

To learn more about momentum, click here:

brainly.com/question/1042017

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5. A group of at

Sveta_85 [38]

Answer:

A group of atoms where the magnetic fields of the atoms point in the same direction is a magnetic domain.

Explanation:

In every magnet's magnetic field there is a region where the magnetization is in the same direction. This region is known as magnetic domain.
In the magnetic domain the atoms always points in the same magnetic filed direction.
All the atom's magnetic field align in one particular direction.
This region where atoms align is called as domains.

4 0

2 years ago

N76 [4]

Answer:

Weight

Explanation:

Weight is the downward pull on an object due to gravity.

For example, the moon has less gravity than Earth so we would weigh less on the moon. Our Mass and volume always stay the same but our weight could change.

4 0

2 years ago

A car accelerates uniformly from rest and reaches a speed of 24.3 m/s in 9.1 s. The diameter of a tire is 80.2 cm. Find the numb

BaLLatris [955]

By using first and third equation of motion, the number of revolutions the tire makes during this motion is 43 rev.

ANGULAR MOTION

Since the car accelerate from rest, initial velocity will be zero.

Given that a car accelerates uniformly from rest and reaches a speed of 24.3 m/s in 9.1 s. The following are the given parameters

Initial velocity U = 0

Final velocity V = 24.3 m/s

Time t = 9.1 s

If the diameter of a tire is 80.2 cm, to find the number of revolutions the tire makes during this motion, we must first calculate the distance travelled by the car by using first and third equation of motion of the car.

First equation

V = U + at

Substitute all necessary parameters into the equation.

24.3 = 0 + 9.1a

a = 24.3/9.1

a = 2.67 m/ $s^{2}$

Third Equation of motion

$V^{2} = U^{2} + 2aS$

Substitute all the necessary parameters

$24.3^{2}$ = 0 + 2 x 2.67 x S

590.49 = 5.34S

S = 590.49 / 5.34

S = 110.58 m.

Given that the diameter of a tire is 80.2 cm,

the radius (r) will be 80.2/2 = 40.1 cm

convert it to meter

r = 40.1/100 = 0.401 m

The Circumference of the tire = 2 $\pi$ r

Circumference = 2 x 3.143 x 0.401

Circumference = 2.52 m

Assuming no slipping, number of revolutions = 110.58/2.52

Number of revolutions = 43.89 rev.

Number of revolutions = 43 rev.

Therefore, the number of revolutions the tire makes during this motion is 43 rev.

Learn more about circular motion here: brainly.com/question/6860269

4 0

1 year ago

A basketball player can leap upward 0.42 m. What is the magnitude of his initial velocity at the start of the leap? Use g=9.81 m

Tatiana [17]

Farmula 2gh=vf²-vi²
2×0.42×9.81=0²-vi²
8.2404=vi²
Vi=✓8.2404
Vi=2.87m/sec

8 0

2 years ago

Please help on this one?

ruslelena [56]

Answer:

A, 30V

Explanation:

First combine all resistors to an equivalent resistor. Since they are in series, the equivalent resistance is the sum of all resistor

Req = 20 + 40 + 60 = 120Ω

Using Ohm's law, find the current in the circuit

V = I * R

I = V / R

I = 60V / 120Ω

I = 0.5 A

Now the potential drop across the resistor R3 is the current times R3 resistance, therefore:

Vdrop = 0.5A * 60Ω = 30V

So the potential drop across resistor R3 is 30 V

3 0

2 years ago

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