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Karo-lina-s [1.5K]
1 year ago
14

The conservation of momentum is most closely related to Newton's?

Physics
1 answer:
AleksandrR [38]1 year ago
3 0

The conservation of momentum is most closely related to Newton's third law.

According to the conservation of momentum, momentum is neither created nor destroyed, although it can change from one form to another.

According to Newton's third law, for every action, there is an opposite reaction, and energy is neither created nor destroyed. Rather the energy is changed from the action to the reaction in a given system and the amount of energy remains the same.

Both the conservation of momentum and Newton's third law imply that energy in a system can be converted but the value remains the same in a system and hence is closely related.

To learn more about momentum, click here:

brainly.com/question/1042017

#SPJ4

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2. You will need a magnifying glass and a small piece of scrap paper for this demonstration. a. Go outside on a sunny day and pu
andrew-mc [135]

The focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.

<h3>Focal length</h3>

The focal length, f is the distance from a lens or mirror to the focal point, F.

This is the distance from a lens or mirror at which parallel light rays will meet for a converging lens or mirror or appear to diverge from for a diverging lens or mirror.

A magnifying glass is a converging lens which produces a enlarged, erect and virtual image when an object is placed between the focal point and optical centre.

A magnifying glass will bring to focus at a point sun rays which can cause the paper to catch fire if it is held in place for long.

This point at which the most concentrated ray of light is shining on the paper, is the focal point for that magnifying glass.

Therefore, the focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.

Learn more about about focal length at: brainly.com/question/25779311

4 0
2 years ago
An object is in free fall. After 10 seconds calculate the distance fallen? *
Citrus2011 [14]

Answer:

9.81 × 10 = 98.1 meters

vertical displacement is s=1/2 at^2 + vt

initial vertical velocity is 0 so s=1/2 at^2

a in this instance is gravitational acceleration so 60m= 1/2 (9.81)t^2

solve for t, t = 3.497s. //I corrected this answer as just now I misread horizontal as vertical.

3 0
3 years ago
Read 2 more answers
An elevator weighs 1500 Newtons. Calculate how much potential energy it has when it is lived 500 meters in the air.
avanturin [10]

An elevator has 750,000 J when it is lived 500 meters in the air

Answer: Option D

<u>Explanation:</u>

The expression to find the potential energy completely on the basis of forces that on two objects. It can be written as

potential\ energy (P . E)=m \times acceleration\ due\ to\ gravity\ (g) \times height (h)

Where,

m – mass of object

Acceleration due to gravity =  9.8 \mathrm{m} / \mathrm{s}^{2}

h = 500 meters

Force = 1500 Newton

As we know, according to Newton second law of motion, the force can be expressed in terms of mass and gravity (F= ma). So, the potential energy can be calculated as

P . E=F \times h=1500(500)=750000 J

Hence, an elevator has 750,000 J when it is lived 500 meters in the air.

4 0
3 years ago
An arrow is launched upward with an initial speed of 100 meters per second (m/s). The equations above describe the constant-acce
ankoles [38]

Answer:

d=510.2m

t=10.2s

Explanation:

The formulas for accelerated motion are:

v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}

From them we can get v^2=v_0^2+2ad.

We have:

v-v_0=at\\t=\frac{v-v_0}{a}

And substitute:

x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}

We multiply both sides by 2a, and continue:

2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2

Being d the displacement x-x_0, we have v^2=v_0^2+2ad

For our exercise, we will write this as:

d=\frac{v^2-v_0^2}{2a}

And taking upwards direction positive and imposing final velocity 0m/s (for maximum height), we have:

d=\frac{-v_0^2}{2a}=\frac{-(100m/s)^2}{2(-9,8m/s^2)}=510.2m

For the time we use:

t=\frac{v-v_0}{a}=\frac{-v_0}{a}=\frac{-(100m/s)}{(-9.8m/s^2)}=10.2s

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3 years ago
I really don’t know what it is to me they r all the same
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The moon lacks an atmosphere compared to the Earth. Hope this helps!
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3 years ago
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