To do this, you need to multiply out the expressions. This is a bit tedious, but remember like FOIL for binomials, for these trinomials you must multiply each term. If you need a step-by-step, I'd be happy to provide it. Let me know.

Once you have simplified the expression, you get

-x-9/2x-4

But, the problem stipulates that a must equal 1. We can equivalently factor out the negative sign and put it on the denominator with no change to write

x+9/-(2x-4) = x+9/-2x+4

So, seeing where each coefficient corresponds between the two expressions, you get a = 1, b = 9, c = –2, and d = 4.

8 0

2 years ago

Which questions best describes: A tire manufacturer has a 60,000 mile warranty for tread life. The manufacturer considers the ov

seropon [69]

This question is incomplete because the answer choices were not provided. The complete question was obtained from google as:

A tire manufacturer has a 60,000 mile warranty for tread life. The manufacturer considers the overall tire quality to be acceptable if less than 5% are worn out at 60,000 miles. The manufacturer tests 250 tires that have been used for 60,000 miles. They find that 3.6% of them are worn out. With this data, we test the following hypotheses.

H0: The proportion of tires that are worn out after 60,000 miles is equal to 0.05.

Ha: The proportion of tires that are worn out after 60,000 miles is less than 0.05.

In order to assess the evidence, which question best describes what we need to determine?

a. If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?

b. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be 5%?

c. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be less than 5%?

d. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be 3.6%?

e. If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be less than 5%?

Answer:

Option A is the correct question - If we examine a sample of tires used for 60,000 miles and determine the proportion that is worn out, how likely is that proportion to be 3.6% or less?

Step-by-step explanation:

The correct question that describes what needs to be determined is expressed in option A as this will give us p-value and we will guide us in deciding whether to keep or reject the null hypothesis

Thus option A is the correct question - If we examine a sample of tires used for 60,000 miles and determine the proportion that is worn out, how likely is that proportion to be 3.6% or less?

7 0

3 years ago