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zalisa [80]
3 years ago
5

You and two friends buy snacks for a field trip. Using the

Mathematics
1 answer:
stepladder [879]3 years ago
7 0

Answer:

13.15

Step-by-step explanation:

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Is it correct way? answer in the picture​
sattari [20]

Answer:56

Step-by-step explanation:

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3 years ago
Read 2 more answers
C' (-3,5)
kherson [118]

Answer:

D. a reflection over the y-axis

5 0
3 years ago
Read 2 more answers
1.) What is the domain and range of the function in the graph?
olga_2 [115]

Answer:

Domain → (-∞, ∞)

Range → (-2, ∞)

Step-by-step explanation:

1). Domain of a function is defined by the input values (set of x-values) and Range of the function is defined by the output values (set of y-values).

From the graph attached,

Function is defined for all real values of x.

Therefore, domain of the function will be (-∞, ∞).

On y-axis values of the function vary from -2 (excluding 2) to positive infinity.

Therefore, range of the function will be (-2, ∞).

2). Average rate of change of a function in the interval (a, b) is defined by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

By using this expression we can find the average rate of change in the given interval.

Please give the correct interval for which the average rate of change is to be calculated.

8 0
3 years ago
I'LL DEFINITELY MARK YOU BRAINLIST CAN U HELP ME IN THIS ( options are in the 2nd slide )
Marta_Voda [28]

Answer:

5 AND 6 ARE CORRECT OPTIONS

5 0
3 years ago
If you place a cup of 210 degree Fahrenheit coffee on a table in a room that is 68 degrees fareinheit, and ten minutes later, it
Lana71 [14]
Newton's Law of Cooling

Tf=Ts+(Ti-Ts)e^(-kt)   where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid.  So we need to find k first.

200=68+(210-68)e^(-10k)

132=142e^(-10k)

132/142=e^(-10k)

ln(132/142)=-10k

k=-ln(132/142)/10

k≈0.0073  so 

T(t)=68+142e^(-0.0073t)  so how long until it reaches 180°?

180=68+142e^(-0.0073t)

112=142e^(-0.0073t)

112/142=e^(-0.0073t)

ln(112/142)=-0.0073t

t= -ln(112/142)/(0.0073)

t≈32.51 minutes


8 0
3 years ago
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