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3 years ago

Variation table of this g(x)=2x^3 -x^2 -4x +6

Mathematics

1 answer:

Mrac [35]3 years ago

7 0

Answer:

$2x^{3} - x^{2} - 4x +6$

2x-x-4 $x^{3-2}$ + 6

-3x+6

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The Math Club bought 16 graphing calculators for $765. The TI-70 model costs $40 and

Afina-wow [57]

Answer:

They bought 5

Step-by-step explanation:

65x+40y=765

65(5)+40(11)=765

5 0

3 years ago

Solve for a 2a + ab = b

amid [387]

Answer: a= b/ b+2

Step 1: factor out variable a.

a(b+2)= b

Step 2: divide both sides by b+2.

a(b+2)/ b+2 = b/b+2

6 0

3 years ago

The transformation of 'f' is represented by 'g'. Write a rule for g. f(x)=\root(3)(x). Then show your check steps.

podryga [215]

Answer:

$g(x)=-2\sqrt[3]x$

$g(x) = -2f(x)$

Step-by-step explanation:

Given

$f(x) = \sqrt[3]x$

Required

Write a rule for g(x)

See attachment for grid

From the attachment, we have:

$(x_1,y_1) = (-1,2)$

$(x_2,y_2) = (1,-2)$

We can represent g(x) as:

$g(x) = n * f(x)$

So, we have:

$g(x) = n * \sqrt[3]x$

For:

$(x_1,y_1) = (-1,2)$

$2 = n * \sqrt[3]{-1}$

This gives:

$2 = n * -1$

Solve for n

$n = \frac{2}{-1}$

$n = -2$

To confirm this value of n, we make use of:

$(x_2,y_2) = (1,-2)$

So, we have:

$-2 = n * \sqrt[3]1$

This gives:

$-2 = n * 1$

Solve for n

$n = \frac{-2}{1}$

$n = -2$

Hence:

$g(x) = n * \sqrt[3]x$

$g(x)=-2\sqrt[3]x$

or:

$g(x) = -2f(x)$

4 0

3 years ago

Solve for x: -5|x+1|=10

MrMuchimi

-5|x + 1| = 10
-5 -5
|x + 1| = -2

No Solution

8 0

4 years ago

One number is three less than four times another. If their difference is 48, what is the larger number?

givi [52]

Answer:

Step-by-step explanation:

Let x be the number and y be the another one.

x=4y-3

x-y=48

Substitute x=4y-3 into x-y=48

(4y-3)-y=48

3y=51

y=17

[Since we know x is larger than y (4y-3), we need to use y to calculate out x.]

Substitute y=17 into x=4y-3

x=68-3

x=65

3 0

4 years ago