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viktelen [127]
2 years ago
5

Variation table of this g(x)=2x^3 -x^2 -4x +6

Mathematics
1 answer:
Mrac [35]2 years ago
7 0

Answer:

2x^{3} - x^{2}  - 4x +6

2x-x-4x^{3-2}+ 6

-3x+6

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the function h=-16t^2+48t represents the height h (in feet) of a kickball t seconds after it is kicked from the ground
Julli [10]

Answer:

36 feet

Step-by-step explanation:

Given

h(t) = -16t^2 + 48t

Required

Determine the maximum height attained

First, calculate the time to reach maximum height;

In a quadratic equation;

y = ax^2 + bx + c

The maximum is:

x = -\frac{b}{2a}

So, we have:

t = -\frac{b}{2a}

Where

a = -16; b = 48

So:

t = -\frac{b}{2a}

t = -\frac{48}{2 * -16}

t = -\frac{48}{-32}

t = \frac{48}{32}

t = 1.5

The maximum height is at: t = 1.5

So, we have:

h(t) = -16t^2 + 48t

h_{max}=-16 * 1.5^2 + 48 * 1.5

h_{max}=36

6 0
3 years ago
Please help will mark brainliest
kolbaska11 [484]

It is A due to the fact that the over all angle is 90 degrease.

3 0
2 years ago
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Convert to a mixed number, reduce when possible (-3.4 x -6.6)
julia-pushkina [17]

The answer would be 22,44

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3 years ago
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Please can u answer these for me
ziro4ka [17]
18 . it's increasing by 5 every time so the next one after 23 is 28
4 0
3 years ago
Parallel / Perpendicular Practice
deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

  1. Neither
  2. ║
  3. Neither
  4. ⊥
  5. ║
  6. Neither
  7. Neither
  8. Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; m_1 = -\dfrac{1}{m_2}

1. The given equations are in the slope and intercept form

\ y = 3 \cdot x + 1

The slope, m₁ = 3

y = \dfrac{1}{3} \cdot x + 1

The slope, m₂ = \dfrac{1}{3}

Therefore, the equations are <u>neither</u> parallel or perpendicular

  • Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

y = 5 \cdot x -\dfrac{7}{2}

Therefore, the two equations are <u>parallel</u>

  • ║

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

y = 2 -\dfrac{1}{2}  \cdot x

Slope, m₁ = -\dfrac{1}{2}

y = \dfrac{1}{2}  \cdot x - 2

Slope, m₂ = \dfrac{1}{2}

The slopes

Therefore, m₁ ≠ m₂

m_1 \neq -\dfrac{1}{m_2}

The lines are <u>Neither</u> parallel nor perpendicular

  • <u>Neither</u>

4. The given equations are;

2·y - x = 2

y = \dfrac{1}{2} \cdot   x +1

m₁ = \dfrac{1}{2}

y = -2·x + 4

m₂ = -2

Therefore;

m_1 \neq -\dfrac{1}{m_2}

Therefore, the lines are <u>perpendicular</u>

  • ⊥

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, y = \dfrac{3}{4} \cdot x + 3

Second equation, y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}

Therefore, m₁ = m₂, the lines are <u>parallel</u>

  • ║

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = \dfrac{13}{5}

Therefore, the two equations are <u>neither</u> parallel nor perpendicular

  • <u>Neither</u>

7. The equations are;

2·x + 6·y = -3

Which gives y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}

12·y = 4·x + 20

Which gives

y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}

m₁ ≠ m₂

m_1 \neq -\dfrac{1}{m_2}

  • <u>Neither</u>

8. 2·x - 5·y = -3

Which gives; y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}

5·x + 27 = 6

x = -\dfrac{21}{5}

  • Therefore, the slopes are not equal, or perpendicular, the correct option is <u>Neither</u>

Learn more here:

brainly.com/question/16732089

6 0
3 years ago
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