-43 - 4r = 3 - 27r
Add 27r to both sides. -43 - 4r + 27r = 3 -27r + 27r or -43 + 23r = 3
Add 43 to both sides. -43 + 43 +23r = 3 + 43 or 23r = 46.
Divide both sides by 23 to get r by itself. 23r / 23 = 46 / 23 or r = 2
r = 2
1. Definition of bisector
2. ASA congruence theorem or ASA Postulate
Answer:
Step-by-step explanation:
You didn't mark your graph but I'm assuming the point is (1,2)
You notice how the function stops at the point? x and y can not be above that point because there is no line above it.
The domain of the function means what can x possibly be.
The maximum value of x in this function is 1 because that's the x value of the point where the function ended. This means x can at most be one or x≤1. So the domain is x≤1.
The range of the function means what can y possibly be.
The maximum value of y in this function is 2 because that's the y value of the point where the function ended. This means y can at most be two or y≤2. So the range is y≤2.
Answer:
x=5 and y=5
Step-by-step explanation:
You "plug" one equation into the other, to get a new equation that only has one variable (x or y), then you can simplify that and have your answer.
So let's plug the first into the second:
First, we convert the first equation into an x=... form. For this one, this means moving the +y to the other side:
x = 10 - y
Now we substitute 10-y for x in the second equation:
So 2x+4y=30 becomes:
2(10-y) + 4y = 30
And simplify that:
20 - 2y + 4y = 30
20 + 2y = 30
2y = 30-20
2y = 10
y = 5
This is the first answer! If we put this into the first equation, we get:
x = 10 - 5 = 5
Now we have both answers, x=5 and y=5
let's firstly convert the mixed fractions to improper fractions and then subtract, bearing in mind that the LCD of 4 and 2 is 4.
![\bf \stackrel{mixed}{8\frac{3}{4}}\implies \cfrac{8\cdot 4+3}{8}\implies \stackrel{improper}{\cfrac{35}{4}}~\hfill \stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{35}{4}-\cfrac{15}{2}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{(1)35~~-~~(2)15}{4}}\implies \cfrac{35-30}{4}\implies \cfrac{5}{4}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B8%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B8%5Ccdot%204%2B3%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B35%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B7%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B7%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B15%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B35%7D%7B4%7D-%5Ccfrac%7B15%7D%7B2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%204%7D%7D%7B%5Ccfrac%7B%281%2935~~-~~%282%2915%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B35-30%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B4%7D)
