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2 years ago

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What is Newton's third law of motion? Give an example.

1 answer:

Vikentia [17]2 years ago

7 0

Answer: Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation: hope this helps :)

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vladimir2022 [97]

Answer:

golf all on grass covered hill in sunlight

Explanation:

someone pouring/spinning top has a lot of motion going on. a roller coaster has force acting on it which increases the motion.

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2 years ago

Read 2 more answers

3.The space heater in a room does not have a fan, but after a few minutes you feel warm air moving by you. What type of energy t

Natali [406]

Heat transfer

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6 0

2 years ago

What is the magnite of the net displacement of the mouse?

agasfer [191]

Complete Question

A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?

Answer:

The values is $s = 7.49 \ m$

Explanation:

From the question we are told that

The distance it travels eastward is $x = 5.0 \ m$

The distance it travel towards the southeast is $l = 3.0\ m$

The distance it travel towards the south is $z = 1 \ m$

Let x-axis be east

y-axis south

z-axis into the ground

The angle made between east and south is $\theta = 45^o$

The displacement toward x-axis is

$x = 5 + 3cos(45)$

$x = 7.12$

The displacement toward the y-axis is

$y = 3 * sin (45)$

$y = 2.123$

Now the overall displacement of the rat is mathematically evaluated as

$s = \sqrt{7.12^2 + 2.12^2 + 1^2}$

$s = 7.49 \ m$

3 0

3 years ago

A 0.300 kg ball, moving with a speed of 2.5 m/s, has a head-on collision with at 0.600 kg ball initially at rest. Assuming a per

FrozenT [24]

Answer:

1.25 m/s

Explanation:

Given,

Mass of first ball=0.3 kg

Its speed before collision=2.5 m/s

Its speed after collision=2 m/s

Mass of second ball=0.6 kg

Momentum of 1st ball=mass of the ball*velocity

=0.3kg*2.5m/s

=0.75 kg m/s

Momentum of 2nd ball=mass of the ball*velocity

=0.6 kg*velocity of 2nd ball

Since the first ball undergoes head on collision with the second ball,

momentum of first ball=momentum of second ball

0.75 kg m/s=0.6 kg*velocity of 2nd ball

Velocity of 2nd ball=0.75 kg m/s ÷ 0.6 kg

=1.25 m/s

4 0

2 years ago

The distance between two particles is 2 centimeters. If the distance is increased to 4 centimeters, the force will be ?

postnew [5]

Answer:

The new force is 1/4 of the previous force.

Explanation:

Given

$Initial\ Distance = 2cm$ ---- $r_1$

$New\ Distance = 4cm$ --- $r_2$

Required

Determine the new force

Let the two particles be q1 and q2.

The initial force F1 is:

$F_1 = \frac{kq_1q_2}{r_1^2}$ --- Coulomb's law

Substitute 2 for r1

$F_1 = \frac{kq_1q_2}{2^2}$

$F_1 = \frac{kq_1q_2}{4}$

The new force (F2) is

$F_2 = \frac{kq_1q_2}{r_2^2}$

Substitute 4 for r2

$F_2 = \frac{kq_1q_2}{4^2}$

$F_2 = \frac{kq_1q_2}{4*4}$

$F_2 = \frac{1}{4}*\frac{kq_1q_2}{4}$

Substitute $F_1 = \frac{kq_1q_2}{4}$

$F_2 = \frac{1}{4}*F_1$

$F_2 = \frac{F_1}{4}$

The new force is 1/4 of the previous force.

3 0

2 years ago