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ankoles [38]
3 years ago
12

Where is the frequency of infrasound in relation to the range of a human's ability to hear?

Physics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

D

Explanation:

The hearing range is 20-20,000 Hz above 20,000 Hz is called ultrasonic sound and below 20 Hz is called infrasound

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A passenger jet flies from one airport to another 1293 miles away in 2.1hours . Find average speed
JulsSmile [24]

The average speed is 615.7 mph (275.2 m/s)

Explanation:

The average speed of an object gives a measure of how fast an object is moving over a certain time interval. It is a scalar quantity, and it is calculated as follows

v=\frac{d}{t}

where

v is the average speed

d is the distance covered

t is the time interval

For the jet in this problem, we have:

d = 1293 mi is the distance covered

t = 2.1 h is the time interval

Therefore, the average  speed is:

v=\frac{1293}{2.1}=615.7 mph

We can also convert into SI units (m/s), keeping in mind that:

1 mi = 1609 m\\1 h = 3600 s

And so

v=615.7 \frac{mi}{h}\cdot \frac{1609 m/mi}{3600 s/h}=275.2 m/s

Learn more about average speed:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

6 0
4 years ago
A 40.0-$kg$ body is moving in the direction of the positive x axis with a speed of 238 $m/s$ when, owing to an internal explosio
Julli [10]

Answer:

v_3 = 400\ m/s

Explanation:

given,

mass of the body = 40 Kg

speed in x-axis = 238 m/s

mass break into three part

m₁ = 7 kg

v₁ = 356 m/s (along the positive y axis)

m₂ = 4.5 kg

v₂ = 357 m/s(along the negative x axis)

m₃ = 40 - (7 + 4.5) = 28.5 Kg

v₃ = ?

using conservation of momentum

MV = m₁v₁ + m₂v₂ + m₃v₃

(40)(238) \hat{i} = (7)(356) \hat{j} - (4.5)(357) \hat {i} + 28.5 v_3

(9520) \hat{i} = 2492 \hat{j} - 1606.5\hat {i} + 28.5 v_3

11126.5 \hat{i} - 2492 \hat{j} = 28.5 v_3

v_3 =390.40 \hat{i} - 87.44 \hat{j}

v_3 = \sqrt{390.40^2 + 87.44^2}

v_3 = 400\ m/s

4 0
3 years ago
at maximum extension a bungee cord stores 2.0 X 10^6 J of energy. A 10 kg mass extends the bungee cord 1.3m. what is the maximum
Gnoma [55]

Explanation:

A k E increases While P E Decreases

4 0
3 years ago
Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
3 years ago
Read 2 more answers
A sample of a gas has a volume of 639 cm3 when the pressure is 75.9 kPa. What is the volume of the gas when the pressure is incr
const2013 [10]

Answer:

388 cm^3

Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

pV=const.

which can also be rewritten as

p_1 V_1 = p_2 V_2

In our case, we have:

p_1 = 75.9 kPa is the initial pressure

V_1 = 639 cm^3 is the initial volume

p_2 = 125 kPa is the final pressure

Solving for V2, we find the final volume:

v_2 = \frac{p_1 V_1}{p_2}=\frac{(75.9)(639)}{125}=388 cm^3

7 0
3 years ago
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