Answer:
C) 4.0 m/s²
Explanation:
Given data
- Applied force (F): 120 Newton
- Mass of the object (m): 30 kilograms
- Acceleration of the object (a): to be determined
We can find the acceleration of the object using Newton's second law of motion.
F = m . a
a = F / m = 120 N / 30 kg = 4.0 m/s²
The acceleration of the object is 4.0 m/s².
A ) The first ball:
h = v o * t - g t² / 2
19.6 = 14.7 t + 9.8 t²/2
4.9 t² + 14.7 t - 19.6 = 0
t 1/2 = (-14.7 +/- √216.09+384.16 ) / 9.8 = 9.8/9.8 = 1 s
The second ball:
v = v o - g t
0 = 14.7 - 9.8 t
9.8 t = 14.7
t = 1.5 ( upward )
h = 19.6 + 14.7 - 9.8 * 1.5 = 30.625 m
30.625 = 9.8 * t²/2
t² = 6.25
t = 2.5 s ( downward )
1.5 s + 2.5 s = 4 s
The difference: 4 s - 1 s = 3 s.
B ) The first ball:
v = v o + g t = 14.7 + 9.8 * 1 = 24.5 m/s
The second ball:
v = g * t = 9.8 * 3 = 24.5 m/s
C ) d 1 = 14.7 * 0.8 + 9.8 * 0.8²/2 = 11.76 + 3.136 = 14.896 m
d 2 = 14.7 * 0.8 - 9.8* 0.8²/2 = 11.76 - 3.136 = 8.624 m
d 1 + d 2 = 14.896 + 8.624 = 23.52 m
<span>The appearance or quality of light reflected from the surface of a mineral is called luster.
Color refers to the color - it is self-explanatory. Cleavage is where the minerals break.
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Accelerating objects are objects which are changing their velocity - either the speed (i.e., magnitude of the velocity vector) or the direction. An object undergoing uniform circular motion is moving with a constant speed. ... The net force acting upon such an object is directed towards the center of the circle.
To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.
The work done would be defined as
Where,
PE = Potential Energy
KE = Kinetic Energy
Where,
m = Mass
g = Gravitational energy
h = Height
v = Velocity
Considering power as the change of energy as a function of time we will then have to
The rate of mass flow is,
Where,
= Density of water
A = Area of the hose
The given radius is 0.83cm or m, so the Area would be
We have then that,
Final the power of the pump would be,
Therefore the power of the pump is 57.11W