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Aneli [31]
1 year ago
6

Allen traveled for 7 hours at a constant rate of 40 miles per hour. Anna traveled the same distance at a constant rate of 50 mil

es per hour.
How long did it take Anna to travel the same distance as Allen?

Drag the steps in the correct order to solve the problem.

Mathematics
1 answer:
TEA [102]1 year ago
3 0

Here is the correct order of the step:

Identify: Anna's time is the unknown

Strategize : let x = Anna's time

Set up : 7(40) = x(50)

Solve: x = 5.6

Check: 7(40) = 5.6(50)

<h3>What is Anna's time?</h3>

The first step is to determine the distance Allen travelled:

Distance = average speed x time

40 x 7 = 280 miles  

The second step is to determine the time it took Anna to travel 280 miles.

Time = distance / average speed

280 / 50 = 5.6 hours

To learn more about average speed, please check: brainly.com/question/21734785

#SPJ1

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What is 20% of 5 Please Help
Softa [21]
Hello there!

Start by asking yourself:"How to find the percentage of a number?"

We need to use the equation y = P% * x

In this case, the y is 20%

Y = P% * X

Y = 20% * X

Now we need to convert the percentage to decimal

P = 20%/100

P = 0.2

Then go back to the equation

Y= 0.2 * 5

Y = 1

The answer is 1

I hope the steps are easy to understand and hopefully the answer helps!

As always, I'm glad to help you today!
4 0
3 years ago
Which equation is true for the value b= 10?
ArbitrLikvidat [17]
The answer to the question is D
7 0
2 years ago
Read 2 more answers
What other information do you need to prove ΔABE is congruent to ΔEDA by SSS?
Stels [109]

To prove ΔABE is congruent to ΔEDA by SSS we need that EAC should be an equilateral triangle.

What is an equilateral triangle?

A triangle is said to be equilateral if each of its three sides is the same length. In the well-known Euclidean geometry, an equilateral triangle is also equiangular, meaning that each of its three internal angles is 60 degrees and congruent with the others.

Here, we have

AEC is a triangle in which B∈ AC and D∈ EC

Such that,

∠ABE = 90°,

∠ADE = 90°,

Also, BC = CD

Now, we have to prove that :

Δ ABE is congruent to Δ EDA

Proof :

If EAC is an equilateral triangle,

By the property of an equilateral triangle,

EA = AC = EC

If AC = EC

AB + BC = ED + CD

AB + CD = ED + CD

AB = ED

Also, AE = AE ( common segment )

Now, if in two right triangles hypotenuse are equal and any corresponding legs are equal,

Then, the other legs must be equal,

That is, BE = DA,

Hence, by the SSS postulate of congruence,

Δ ABE ≅ Δ EDA

Hence, to prove ΔABE is congruent to ΔEDA by SSS we need that EAC should be an equilateral triangle.

To learn more about the equilateral triangle from the given link

brainly.com/question/15294703

#SPJ4

7 0
1 year ago
PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of
Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

8 0
3 years ago
Read 2 more answers
A rock is thrown vertically upward from the surface of an airless planet. It reaches a height of s = 120t - 4t2 meters in t seco
12345 [234]

Answer:

Step-by-step explanation:

Given that a rock is thrown vertically upward from the surface of an airless planet. It reaches a height of s(t) = 120t - 4t^2

where t is expressed in seconds

The rock goes upto a height where the velocity becomes 0 and then it starts falling down by gravity

Velocity at time t = s'(t) = 120-8t

This becomes 0 when t =15 seconds

Hence at 15th second the rock starts falling and upto

s(15) = 120(15)-4(15^2)\\= 900 metres high it goes

The time taken to reach highest point is = 15 seconds.

6 0
3 years ago
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