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vekshin1
3 years ago
9

What is the opposite of dividing by 21? A. dividing by 21 B. multiplying by 21 C. subtracting 21 D. adding 21​

Mathematics
1 answer:
Illusion [34]3 years ago
5 0

Answer:

the correct answer is option B

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F(x) = (x + 2)/(x2 - 16)
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(-2,8) This is a answer:)
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3 years ago
Suppose there are two circles where the radius of one circle is twice the radius of the other circle. Each circle has an arc whe
Artemon [7]

Answer:

L=2l where l,L denote arc lengths of two circles

Step-by-step explanation:

Let l,L denote arc lengths of two circles, r,R denote corresponding radii and

\alpha _1\,,\alpha _2 denote the corresponding central angles.

So,

l=r\alpha _1 and L=R\alpha _2

This implies \alpha _1=\frac{l}{r} and \alpha _2=\frac{L}{R}

As each circle has an arc where the measures of the corresponding central angles are the same, \alpha _1=\alpha _2

\frac{l}{r}=\frac{L}{R}

As radius of one circle is twice the radius of the other circle,

R=2r

\frac{l}{r}=\frac{L}{2r}\\\frac{l}{1} =\frac{L}{2}\\L=2l

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2 years ago
How do you figure out basketball stats?​
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8 0
3 years ago
a sayian's power level is 400 septillion if he goes super sayian 3 and it multiplies his power by 900 trillion what is his power
QveST [7]
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3 years ago
Read 2 more answers
Find the height of a square pyramid that has a volume of 75 cubic feet and a base length of 5 feet.
Rudiy27

Answer:

9 ft

Step-by-step explanation:

Let's begin with the formula for the volume of a square pyramid.  If s is the base length, then the area of the base is s^2.  The volume of the pyramid is then V = (1/3)(base area)(height).  We know the volume and the base length (s), and want to find the height.  Solving V = (1/3)(base area)(height)

for height, we get:

3V = (base area)(height), or

    3V

---------------- = height

base area

Substituting 75 ft^3 for V and (5 ft)^2 for base area, we get:

               3(75 ft^3)              9 ft

height = ------------------ = ----------------- = 9 ft

                 25 ft^2                   1

3 0
3 years ago
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