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Radda [10]
3 years ago
13

HELP TIMED!!

Mathematics
2 answers:
Gwar [14]3 years ago
7 0

Answer:

50%

Step-by-step explanation:

Its a deck and its suffled

AysviL [449]3 years ago
7 0

Answer:

\frac{8}{52} = 0.15384615384 = 15.38%

Step-by-step explanation:

There are 4 7s and 4 queens so

\frac{4}{52} + \frac{4}{52} = \frac{8}{52}

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It takes 5 days to repair 1,250 meters of road. At this rate, how many days will it take to repair 8 kilometers of road?
dolphi86 [110]

Answer :

no. of days used to repair 1250m of road = 5

no. of days used to repair 1m of road = 5/1250

no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days

6 0
3 years ago
Read 2 more answers
5 questions
zzz [600]

This is a comment---

Are you acually in middle school because this is algebra 2 and im learning this now in High school

4 0
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Anyone listens to Texako, Summrs, Ect ?
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Step-by-step explanation:

4 0
1 year ago
Paul is saving for a down payment to buy a house. The account earns 13% interest compound quarterly, and he wants to have $15,00
Tatiana [17]

Answer:

The principal must be = $8991.88

Step-by-step explanation:

Formula for compound interest is:

A = P(1 + \frac{r}{n})^{nt}

Where A is the amount after 't' years.

P is the principal amount

n is the number of times interest is compounded each year.

r is the rate of interest.

Here, we are given that:

Amount, A = $15000

Rate of interest = 13 % compounded quarterly i.e. 4 times every year

Number of times, interest is compounded each year, n = 4

Time, t = 4 years.

To find, Principal P = ?

Putting all the given values in the formula to find P.

15000 = P(1 + \frac{13}{400})^{4\times 4}\\\Rightarrow 15000 = P(1 + 0.0325)^{16}\\\Rightarrow 15000 = P(1.0325)^{16} \\\Rightarrow 15000 = P \times 1.66817253\\\Rightarrow P = \dfrac{15000}{1.66817253}\\\Rightarrow P \approx \$8991.88

So, <em>the principal must be = $8991.88</em>

4 0
3 years ago
How do i find the length to the indicated segment?
In-s [12.5K]

Answer:

does the question have a picture

8 0
3 years ago
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