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AlekseyPX
3 years ago
7

In a consumer survey of 500​ people, 106 indicated that they would be buying a major appliance within the next​ month, 42 indica

ted they would buy a​ car, and 11 said that they would buy both a major appliance and a car. How many will purchase only a​ car?
Mathematics
1 answer:
Setler79 [48]3 years ago
5 0

Answer:

is it multiple choice?

Step-by-step explanation:

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I need help on question 2. Any help is appreciated:)
zlopas [31]
All the y values would be 0, since it’s a horizontal line
3 0
3 years ago
HELP
andreev551 [17]

Answer:

A. y = 80x

B. g(x) = 80x

C. To graph the equation, plot a point at (0,0) and a point at (1,80). Connect the points. Continue adding points by moving up $80 and over 1 day.

Step-by-step explanation:

Part A:  

To write an equation, use y= mx where m is the slope, x is the number of days, and y is the rent cost.

x and y remain the same in the equation.

To find m, use the slope formula with (5,465) and (7, 625).

m=\frac{y_2-y_1}{x_2-x_1}= \frac{625-465}{7-5} =\frac{160}{2} =80

It costs $80 a day.

The equation is y = 80x.

Part B:  

Function notation replaces Y as g(x). So the equation is g(x) = 80x.

Part C:

To graph the equation, plot a point at (0,0) and a point at (1,80). Connect the points. Continue adding points by moving up $80 and over 1 day.


6 0
3 years ago
How do I find the simplest form,for this problem 4-2(3+6)+2-2=
levacccp [35]
Try using PEMDAS,
Parentheses
Exponents 
Multiplication
Division
Addition
Subtraction

So just do the problem in that order.

5 0
3 years ago
The question is evaluate x÷1.2 for each value of x         x=40.8
Aleks [24]
x:1.2\\\\x=40.8\to40.8:1.2=34

4 0
3 years ago
Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.
Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is Q(x,y) is predicate that x then x^{2}. where x,y are rational numbers.

a)

when x=-2, y=1

Here -2 that is x  satisfied. Then

(-2)^{2}

4 this is wrong. since 4>1

That is x^{2}>y^{2} Thus Q(x,y) =Q(-2,1)is false.

b)

Assume Q(x,y)=Q(-5,2).

That is x=-5, y=2

Here -5 that is x this condition is satisfied.

Then

(-5)^{2}

25 this is not true. since 25>4.

This is similar to the truth value of part (a).

Since in both x satisfied and x^{2} >y^{2} for both the points.

c)

if Q(x,y)=Q(3,8) that is x=3 and y=8

Here 3 this satisfies the condition x.

Then 3^{2}

9 This also satisfies the condition x^{2}.

Hence Q(3,8) exists and it is true.

d)

Assume Q(x,y)=Q(9,10)

Here 9 satisfies the condition x

Then 9^{2}

81 satisfies the condition x^{2}.

Thus, Q(9,10) point exists and it is true. This satisfies the same values as in part (c)

6 0
3 years ago
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