We have:
Volume of cone = 535 cm³ at the maximum
Height of cone= 8cm
We know the formula to find volume of cone is

We need to find the radius of the base of the cone





to the nearest one decimal place
The width of the opening of the cone is the diameter of the circle. Diameter is twice the radius, hence 2×36.9=73.8 cm
Answer:
A
Step-by-step explanation:
hope this helps please brainiest
A^2 + 16^2 = 20^2
(Third one)
diagonal is sqrt of (s^2 x 2)
8^2 = 64
64*2 = 128
sqrt(128) = 11.3137
round answer as needed
9514 1404 393
Answer:
(9√3 -3π/2) ft^3 ≈ 10.88 ft^3
Step-by-step explanation:
The area of the hexagon is given by the formula ...
A = (3/2)√3·s^2 . . . . for side length s
The area of the hexagonal face of this solid is ...
A = (3/2)√3·(2 ft)^2 = 6√3 ft^2
__
The area of the circular hole in the hexagonal face is ...
A = πr^2
The radius is half the diameter, so is r = (2 ft)/2 = 1 ft.
A = π(1 ft)^2 = π ft^2
Then the area of the "solid" part of the face of the figure is ...
A = (6√3 -π) ft^2
__
The volume is ...
V = Bh . . . . . where B is the area of the base of the prism, and h is its height
V = ((6√3 -π) ft^2)(3/2 ft) = (9√3 -3π/2) ft^3 ≈ 10.88 ft^3