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Temka [501]
3 years ago
13

The sum of two rational numbers will always be

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0

The sum of two rational numbers will always be <u>rational</u>

<u></u>

\frac{a}{b} +\frac{c}{d} =\frac{ad+bc}{bd}, therefore it will always be rational

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14/25, 13%, 0.28, 7%, 21/100, 0.15 from least to greatest
lozanna [386]

Answer:

7%, 0.28, 0.15, 13%, 21/100, 14/25

Step-by-step explanation:

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6 0
4 years ago
Find a polynomial f(x) of degree 3 with real coefficients and the following zeros. 4, 2-1
natima [27]

Answer:

P(x)=x^3-5x^2+2x+8

Step-by-step explanation:

If the polynomial has the following zeros: x= 4, x=2, and x=-1, then it must have the following factors which guarantee the polynomial will render zero at the given points:

P(x)=C (x-4)\, (x-2) \,(x+1)

where C is any multiplicative constant. Since there is no other condition imposed on the polynomial, we can adopt a simple constant C = 1 to facilitate our final calculation of writing the polynomial in standard form:

P(x)=(x-4)\, (x-2) \,(x+1)\\P(x)=(x^2-2x-4x+8)\,(x+1)\\P(x)= (x^2-6x+8)\,(x+1)\\P(x)=x^3+x^2-6x^2-6x+8x+8\\P(x)=x^3-5x^2+2x+8

3 0
3 years ago
△RST is mapped to △R′S′T′ using the rule (x,y)→(x,−y) followed by (x,y)→(3x,3y)
Vadim26 [7]

Remember:

a) (x,y) => (x, -y) is a reflection across X axis

b) (x,y) => (-x,y) is a reflection across Y axis

Here △RST is mapped to △R′S′T′ using the rule (x,y)→(x,−y)

Hence it is a reflection across X axis.

The size of the triangle does not alter.

But when this is followed by (x,y)→(3x,3y), the lengths increase by a factor 3.

Hence the triangles do not remain congruent.

△RST is not congruent to △R′S′T′ because the rules do not represent a sequence of rigid motions.

Option A) is the right answer

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS I WILL MARK BRAIINLIST!!
Reptile [31]

Answer:

10

Step-by-step explanation:

First solve for x. HI = 2x, IJ = 4x - 10, and the whole length HJ = 4x.

So 2x + 4x - 10 = 4x.

6x - 10 = 4x

6x - 4x - 10 = 4x - 4x

2x - 10 = 0

2x - 10 + 10 = 0 + 10

2x = 10

x = 5.

IJ is 4x - 10, so it becomes 4(5) - 10

20 - 10 = 10

7 0
3 years ago
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