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3 years ago

5

Two friends met up for coffee and dessert. Each friends got a medium drink and two cupcakes, and one friend bought a mug for $12

. The friend who bought the mug paid for their order, and the total was $29.00.
plz helppppp

2 answers:

Law Incorporation [45]3 years ago

8 0

Answer:

complete question ...

Crank3 years ago

4 0

Answer:

each cupcake was $6.75. I saw this question earlier

Step-by-step explanation:

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Gary's contract says he must work at least 20 hours per week. Gary is paid $15.50 per hour. Gary is also paid $50 per week. Gary

Rasek [7]

Answer: Gary needs to work more than 25hours for the week to earn above $400.

Step-by-step explanation:

For Gary to be paid $50 per week means he worked $50/ $15.50= 3.23 hours for the week.

To make over $400 this week he needs to work for

400/15.50 = 25.81 hours and more for the week to earn above $400

8 0

2 years ago

Write an equation for a circle with center at (5,-2) and diameter of 8 centimeters.

mars1129 [50]

Answer:

$(x-5)^2+(y+2)^2=16$

Step-by-step explanation:

lol brainlessly...

General Circle function: $(x-h)^2+(y-k)^2=r^2$ , where h is the x-coordinate of the center, k is the y-coordinate of the center, and r is the radius.

The radius of the circle is half the diameter so: 8 / 2 = 4

The x-coordinate of the circle is 5

The y-coordinate of the circle is -2

Plug in.

$(x-5)^2+(y-(-2))^2=4^2$

$(x-5)^2+(y+2)^2=16$

5 0

3 years ago

Which measures of central tendency would be affected if the outlier 11 was added to the following set 27,20,34,37,21,42,39

MrRa [10]

Answer:

Median will not be affected by the outlier.

Step-by-step explanation:

With the outlier, the mean will be dragged way down. The median will likely be about the same. Mean is non-resistant to outliers, median is resistant.

Hope this helps!

5 0

2 years ago

As voters exit the polls, you ask a representative random sample of voters if they voted for a proposition. If the true percenta

tresset_1 [31]

Answer:

The probability is 0.057797

Step-by-step explanation:

Consider the provided information.

It is given that true percentage of voters who vote for the proposition is 63%,

Let p is probability of success.

According to the binomial distribution:

$P(x;p,n)=^nC_x(p)^x(1-p)^{(n-x)}$

Substitute n=7, p=0.63 and x=2 in the above formula.

$P(x;p,n)=^7C_2(0.63)^2(1-0.63)^{(7-2)}$

$P(x;p,n)=\frac{7!}{2!5!}(0.3969)(0.37)^{5}\\P(x;p,n)=21(0.3969)(0.37)^{5}\\P(x;p,n)=0.0577974947199\\P(x;p,n)\approx0.057797$

Hence, the probability is 0.057797

8 0

3 years ago

Verify csc^2t-cos t sect= cot^2 t

Ymorist [56]

Rewriting the left hand side,

csc²t - cost sec t

= (1/sin²t)-(cost)(1/cost)

= 1/sin²t - 1

= 1/sin²t - sin²t/sin²t

= (1-sin²t)/sin²t

= cos²t/sin²t

= cot²t

7 0

2 years ago

Read 2 more answers