1. What causes potential energy to change within a system?

Please help I’ll mark brainliest. Thank you :)

Jobisdone [24]

Answer:

a. There are only 5 electrons in 2p. 2p should be filled with 6 electrons prior to 3s and 3p

b. There are 8 electrons in 2p. 2p should be filled only with 6 electrons (not 8)

Explanation:

The typical electron configuration: 1s2 2s2 2p6 3s2 3p6

a. There are only 5 electrons in 2p

=> should be 1s2 2s2 2p6 3s2 3p2

b. There are 8 electrons in 2p

=> should be 1s2 2s2 2p6 3s2 3p1

6 0

2 years ago

Enter your answer in the provided box.S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/molS(monoclinic) + O2(g) → SO2(g) ΔHo rxn=

IgorC [24]

Answer: $\Delta H^0=+0.3kJ/mol$ .

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

$S_{rhombic}+O_2(g)\rightarrow SO_2(g)$ $\Delta H^0_1=-296.06kJ$ (1)

$S_{monoclinic}+O_2(g)\rightarrow SO_2(g)/tex] [tex]\Delta H^0_2=-296.36kJ$ (2)

The final reaction is:

$S_{rhombic}\rightarrow S_{monoclinic}$ $\Delta H^0_3=?$ (3)

By subtracting (1) and (2)

$\Delta H^0_3=\Delta H^0_1-\Delta H^0_2=-296.06kJ-(-296.36kJ)=0.3kJ$

Hence the enthalpy change for the transformation S(rhombic) → S(monoclinic) is 0.3kJ

3 0

3 years ago

In the formation of potassium chloride, the product, KCl, has less energy than the reactants, K and Cl2. This reaction is .

k0ka [10]

if the product has lesser energy than the reactants it means enthalpy change value is positive.so it is endothermic reaction where the heat is absorbed.so kcl will formation will have positive enthalpy change .

7 0

3 years ago

Please help with this

GenaCL600 [577]

1. Double-Replacement reactions

2. Decomposition

3. Combustion

4. Syntesis

5. Single replacement

<h3>Further explanation</h3>

Given

Chemical equations

Required

Type of reaction

Solution

1. 2AgNO₃ + MgCl₂ ⇒ 2AgCl + Mg(NO₃)₂

Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant

2. 2KBr⇒2K +Br₂

Decomposition

Single compound breaks down in to 2 or more products

3. C₃H₈ + 5O₂ ⇒ 4H₂O + 3CO₂

Combustion

Hydrocarbon and Oxygen reaction and form water and carbon dioxide

4. NaO + H₂O ⇒ NaOH

Syntesis

2 or more reactants combine to form a single product

5. Zn + CuCl₂ ⇒ZnCl₂ + Cu

Single replacement

One element replaces another element from a compound

6 0

3 years ago

If the mixing ratio of a parcel of air is 6 grams per kilogram and the relative humidity is 25 percent, the saturation mixing ra

Y_Kistochka [10]

Answer: -

24 grams per kilogram.

Explanation: -

We know that

The mixing ratio = actual (measured) mass of water vapor (in parcel) in grams / mass of dry (non water vapor) air (in parcel) in kilogram

The saturation mixing ratio = mass of water vapor required for saturation (in parcel) in grams/ mass of dry (non water vapor) air (in parcel) in kilograms

Relative humidity = actual (measured) water vapor content/ maximum possible water vapor amount (saturation)

Thus saturation mixing ratio = Mixing ratio / relative humidity

= 6 / (25/100)

= 24

4 0

3 years ago