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Monica [59]
2 years ago
10

How many mL of 8.00M HCl solution are needed to make a dilution with a final volume of 2,500.ml, and a

Chemistry
1 answer:
kompoz [17]2 years ago
5 0

Answer:

104.1 mL

Explanation:

c1V1 = c2V2

V1 = c2V2/c1 = (0.333 M×2500 mL)/8.00 M

V1 = 104.1 mL

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3 years ago
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8 0
3 years ago
Read 2 more answers
One peanut M&M weighs approximately 2.33 g.
Sphinxa [80]

Answer:

There are 23076 peanut M&M's in 53.768 kg of M&M's.

Explanation:

First we <u>convert 53.768 kg into g</u>:

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Then we <u>divide the total mass of M&M's by the mass of one peanut M&M,</u> in order to calculate the answer:

  • 53768 g / 2.33 g = 23076

So there are 23076 peanut M&M's in 53.768 kg of M&M's.

3 0
2 years ago
What is the concentration of a solution containing 0.32 moles of NaCl in 3.4 liters?
dsp73
Get the molarity we need to divide the number of moles of NaCl by the volume of the solution. So, 0.32 moles NaCl divided by 3.4 L, and that gives 0.094 M NaCl.
5 0
2 years ago
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