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1 year ago

Explain how to draw the electron-dot diagram for oxygen.

Chemistry

1 answer:

AlexFokin [52]1 year ago

7 0

The electron dot diagram for the oxygen atom shows six electrons around the symbol of the atom.

<h3>What is the electron dot diagram?</h3>

The electron dot diagram is the diagram of atoms of elements showing only the valence electrons present in the atom represented with dots.

The electron dot diagram for the oxygen atom is drawn as follows:

The number of valence electrons in oxygen atom is determined; valence electrons = 6
The symbol for the oxygen atom is written
The valence electrons are shown as dots around the symbol of the element.

In conclusion, the electron dot diagram uses dots around the symbol of an atom to show the valence electrons in the atom.

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Gelneren [198K]

Answer:

Maybe they both have valence electrons and can be used in chemical reactions. I could be wrong, I don't have any exact answers.

Explanation:

5 0

3 years ago

to show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configu

sineoko [7]

The aim is to use less space while demonstrating the distribution of electrons in shells

If you want to depict how an atom's electrons are scattered across its subshells, an orbital notation is more suited.

This is due to the fact that some atoms have unique electronic configurations that are not readily apparent from textual configurations.

<h3>How does electron configuration work?</h3>

The placement of electrons in orbitals surrounding an atomic nucleus is known as electronic configuration, also known as electronic structure or electron configuration.

<h3>What sort of electron arrangement would that look like?</h3>

For instance: You can see that oxygen contains 8 electrons on the periodic table.
These 8 electrons would fill in the following order: 1s, 2s, and finally 2p, according to the aforementioned fill order. O 1s22s22p4 would be oxygen's electron configuration.

learn more about electronic configuration here

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7 0

1 year ago

For the reaction PCl5(g) + heat PCl3(g) + Cl2(g), what will happen when the volume is increased?

bogdanovich [222]

This is an aplication of Le Chatelier Principle. So, if you need further details about the theory behind the answer, search for this subject.

Here is the answer and the explanation.

You can realize that 1 mol of reactant produce 2 moles of products, which means that the trend of the reaction is to increase the volume (at constant pressure) or to increase the pressure (at constant volume). If you realease the pressure by increasing the volume, Le Chaelier principle permit you to predict a displacement of the equilibrium to the right (to the products). This is, because the equilibrium will try to restore (increase) the pressure by producing more molecules.

So, the answer is the option B. There will be a shift toward the products.

4 0

3 years ago

1.42 g H2 is allowed to react with 10.4 g N2 , producing 2.14 g NH3 . Part A What is the theoretical yield in grams for this rea

Bad White [126]

Taking into account the reaction stoichiometry, the theorical yield for the reaction is 8.0467 grams of NH₃.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

3 H₂ + N₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂: 3 moles
N₂: 1 mole
NH₃: 2 moles

The molar mass of the compounds is:

H₂: 2 g/mole
N₂: 28 g/mole
NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

H₂: 3 moles ×2 g/mole= 6 grams
N₂: 1 mole ×28 g/mole= 28 grams
NH₃: 2 moles ×17 g/mole= 34 grams

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 28 grams of N₂ reacts with 6 grams of H₂, 10.4 grams of N₂ reacts with how much mass of H₂?

$mass of H_{2} =\frac{10.4 grams of N_{2}x 6 grams of H_{2} }{28 grams of N_{2}}$

<u><em>mass of H₂= 2.2286 grams</em></u>

But 2.2286 grams of H₂ are not available, 1.42 grams are available. Since you have less mass than you need to react with 10.4 grams of N₂, H₂ will be the limiting reagent.

<h3>Definition of theorical yield</h3>

The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Theoretical yield in this case</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 34 grams of NH₃, 1.42 grams of H₂ form how much mass of NH₃?

$mass of NH_{3} =\frac{1.42 grams of H_{2} x 34 grams of NH_{3}}{6grams of H_{2} }$

<u><em>mass of NH₃= 8.0467 grams</em></u>

Then, the theorical yield for the reaction is 8.0467 grams of NH₃.

Learn more about the reaction stoichiometry:

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7 0

1 year ago

Which substance is a compund

Oxana [17]

Answers:
______________________________________________
1) [D]: " CO₂ " .

<u>Note:</u><u> </u> This is the only answer choice given that is composed of: "at least two different elements" .
_______________________________________________
2) [D]: "carbon and hydrogen" {"C" and "H" .} .
_______________________________________________

7 0

3 years ago