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1 year ago

Explain how to draw the electron-dot diagram for oxygen.

Chemistry

1 answer:

AlexFokin [52]1 year ago

7 0

The electron dot diagram for the oxygen atom shows six electrons around the symbol of the atom.

<h3>What is the electron dot diagram?</h3>

The electron dot diagram is the diagram of atoms of elements showing only the valence electrons present in the atom represented with dots.

The electron dot diagram for the oxygen atom is drawn as follows:

The number of valence electrons in oxygen atom is determined; valence electrons = 6
The symbol for the oxygen atom is written
The valence electrons are shown as dots around the symbol of the element.

In conclusion, the electron dot diagram uses dots around the symbol of an atom to show the valence electrons in the atom.

Learn more about electron dot diagram at: brainly.com/question/5835591

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What is the mass in grams of 7.5 x 10^15 atoms of nickel, Ni?

statuscvo [17]

<h3>Answer:</h3>

7.3 × 10⁻⁷ g Ni

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.5 × 10¹⁵ atoms Ni

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Ni - 58.69 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 7.5 \cdot 10^{15} \ atoms \ Ni(\frac{1 \ mol \ Ni}{6.022 \cdot 10^{23} \ atoms \ Ni})(\frac{58.69 \ g \ Ni}{1 \ mol \ Ni})$
Multiply: $\displaystyle 7.30945 \cdot 10^{-7} \ g \ Ni$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

7.30945 × 10⁻⁷ g Ni ≈ 7.3 × 10⁻⁷ g Ni

3 0

3 years ago

Define the following IN YOUR OWN HANDWRITING

k0ka [10]

Answer:

A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity.

Explanation:

5 0

2 years ago

A sample of a substance was determined and contained 1.0g of mg and 1.75g of o. what is the empirical formula? (10 pts)

Juliette [100K]

<span>Total mass = 2.75g Mass % of Mg = 1.0g x 100/2.75g = 36.36 % Mass % of O = 1.75g x 100/2.75g = 63.64 % Mol of Mg = 36.36/24 = 1.515 Mol of O = 63.64/16 = 3.977 Ratio of Mol of Mg and O in the substance = (1.515 : 3.977) x 2 = 3 : 8 The empirical formula of substance is Mg3O8</span>

7 0

3 years ago

In the laboratory, hydrogen gas is usually made by the following reaction: Zn(s) + 2 HCl(aq) → H2(g) + ZnCl2(aq) How many liters

IrinaK [193]

<u>Answer:</u> The volume of hydrogen gas collected over water is 2.13 L

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$