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3 years ago

I dont understand the problem

Mathematics

1 answer:

Roman55 [17]3 years ago

6 0

Answer:

equation of a line:

y = mx+c

1) find the gradient, m

$m = \frac{y2 - y1}{x2 - x1}$

$m = \frac{ - 4 - ( - 4)}{ - 10 - 1}$

$m = 0$

2) find y-intercept, c using coordinate (1,-4)

y = mx + c

-4 = 0(1) + c

c = -4

the equation of line:

y = mx+c

y = 0(x) + c

y = c

y = -4

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20 points help help help

mrs_skeptik [129]

The perimeter of the shape is 94 cm and the area is 462 sq cm.

Step-by-step explanation:

Given,

The radius (r) = 14 cm

To find the area and perimeter of the given shape.

The given shape is $\frac{3}{4}$ of the full circle.

Formula

The perimeter of the circle = 2πr

The perimeter of the given shape = $\frac{3}{4}$ (2πr)+r+r = $\frac{3}{4}$ (2πr)+2r

The area of the circle = πr²

Now,

The perimeter of the given shape = $\frac{3}{4}$ (2× $\frac{22}{7}$ ×14)+2×14 = 94 cm

The area of the given shape = $\frac{3}{4}$ (πr²)

= $\frac{3}{4}$ × $\frac{22}{7}$ ×14² = 462 sq cm

7 0

3 years ago

Read 2 more answers

Katie wants to create a rectangular frame for a picture. She has 60 inches of material. If she wants the length to be 3 more tha

Fofino [41]

Answer:

Largest possible length is <em>21 inches</em>.

Step-by-step explanation:

Given:

Total material available = 60 inches

Length to be 3 more than twice of width.

To find:

Largest possible length = ?

Solution:

As it is rectangular shaped frame.

Let length = $l$ inches and

Width = $w$ inches

As per given condition:

$l = 2w+3$ ..... (1)

Total frame available = 60 inches.

i.e. it will be the perimeter of the rectangle.

Formula for perimeter of rectangle is given as:

$P = 2 \times (Width + Length)$

Putting the given values and conditions as per equation (1):

$60 = 2 \times (w+ l)\\\Rightarrow 60 = 2 \times (w+ 2w+3)\\\Rightarrow 60 = 2 \times (3w+3)\\\Rightarrow 30 = 3w+3\\\Rightarrow 3w = 27\\\Rightarrow w = 9 \ inch$

Putting in equation (1):

$l = 2\times 9+3\\\Rightarrow l = 21\ inch$

So, the answer is:

Largest possible length is <em>21 inches</em>.

6 0

3 years ago

Find y'' by implicit differentiation. 4x^3 + 5y^3 = 4

iVinArrow [24]

$\bf 4x^3+5y^3=4\implies 12x^2+15y^2\cfrac{dy}{dx}=0\implies 4x^2+5y^2\cfrac{dy}{dx}=0
\\\\\\
5y^2\cfrac{dy}{dx}=-4x^2\implies \boxed{\cfrac{dy}{dx}=\cfrac{-4x^2}{5y^2}}\\\\
-------------------------------\\\\
\cfrac{d^2y}{dx^2}=\stackrel{quotient~rule}{\cfrac{-8x(5y^2)~~-~~(-4x^2)(10y)\left( \frac{dy}{dx} \right)}{(5y^2)^2}}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^2+(40x^2y)\left( \frac{-4x^2}{5y^2} \right)}{25y^4}$

$\bf \cfrac{d^2y}{dx^2}=\cfrac{-40xy^2+(40x^2y)\left( \frac{-4x^2}{5y^2} \right)}{25y^4}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^2-\frac{160x^4y}{5y^2}}{25y^4}\implies 
\cfrac{d^2y}{dx^2}=\cfrac{\frac{-200xy^4-160x^4y}{5y^2}}{25y^4}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-200xy^4-160x^4y}{(25y^4)(5y^2)}\implies 
\cfrac{d^2y}{dx^2}=\cfrac{-200xy^4-160x^4y}{125y^6}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^4-32x^4y}{25y^6}$

6 0

3 years ago

Check that all apply

Lena [83]

it's on only B

this the solution

x>2

y>4

hope this helps you

5 0

3 years ago

Factor the expression using the GCF: 15x - 25

Vladimir79 [104]

Answer:

5 (3x - 5)

u take the highest number or HCF of 15 and 25 which will be 5. then multiply it . like u have to multiply 5 with 3x to get 15 x and same like that u have to multiply 5 with -5 and u get -25...

5 0

3 years ago

Read 2 more answers