All categories

3 years ago

I dont understand the problem

Mathematics

1 answer:

Roman55 [17]3 years ago

6 0

Answer:

equation of a line:

y = mx+c

1) find the gradient, m

$m = \frac{y2 - y1}{x2 - x1}$

$m = \frac{ - 4 - ( - 4)}{ - 10 - 1}$

$m = 0$

2) find y-intercept, c using coordinate (1,-4)

y = mx + c

-4 = 0(1) + c

c = -4

the equation of line:

y = mx+c

y = 0(x) + c

y = c

y = -4

You might be interested in

How much water can this container hold?

kirill [66]

Answer: 24429.02

Step-by-step explanation:

4 0

3 years ago

Pls pls pls pls pls pls

Vesna [10]

Answer:

$30

Step-by-step explanation:

One dollar is 17 pesos according to the chart, so 510/17 would be the US dollar price ($30)

6 0

3 years ago

Read 2 more answers

Limited time . 10 points

AfilCa [17]

Answer:

Therefore the value of x is

$x=1\pm\sqrt{19}i$

Step-by-step explanation:

Given:

$x^{2}+20=2x$ which is

$x^{2}-2x+20=0$

To Find:

x = ? using Quadratic Formula

Solution:

For a Quadratic Equation ax² + bx + c = 0 , Formula Method is given as

$x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

On Comparing with above we get

$a=1\\b=-2\\c=20$

Substituting a , b , c in Formula method we get

$x=\dfrac{-(-2)\pm\sqrt{(-2)^{2}-4(1)(20)}}{2\times 1}\\\\x=\dfrac{2\pm\sqrt{-76}}{2}\\\\x=\dfrac{2\pm2\sqrt{19}i}{2}\\Dividing\ by\ 2\ we\ get\\\\x=1 \pm\sqrt{19}i$

Therefore the value of x is

$x=1\pm\sqrt{19}i$

8 0

3 years ago

Please help :D <3. Do not understand this one.

Shtirlitz [24]

Sorry for my messy handwriting but this is the answer

8 0

3 years ago

Set up an equation and solve the following problem.

nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, t = $\dfrac{\textrm d miles}{\textrm s miph}$

Or, t = $\dfrac{\textrm 210 miles}{\textrm s miph}$

For Kent

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, T = $\dfrac{\textrm D miles}{\textrm S miph}$

Or, T = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

∵ Time taken by both is same

So, t = T

Or, $\dfrac{\textrm 210 miles}{\textrm s miph}$ = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴ s = $\dfrac{840}{20}$

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0

3 years ago