<span>Approximately 25.
Of the 5 grades of sand used in the United states, medium sand has particles ranging from 0.25 mm to 0.5 mm. For convenience, I'll use 0.5mm as the diameter of a grain of sand. Human cells range from a volume of 30 cubic micrometers (human sperm cell) up to 4 million micrometers (human egg cell). For the average human cell, I'll use an osteoblast with a volume of 4000 cubic micrometers or a diameter of 2x10^-5 meters.
Now just take the diameter of a grain of sand and divide by the diameter of a human cell.
5 x 10^-4 / 2x10^-5 = 5/2 x 10^(-4 - -5) = 2.5x10^1 = 25
So the diameter of a grain of sand at 0.5 mm is approximately 25 times larger than that of a human cell at 0.02mm</span>
Answer:none
Step-by-step explanation:
We are given a trapezoid TRHY.
Height of the trapezoid = 13 units.
b1 = 21 units and
Area = 215 units squares.
We need to find the length of b2.
We know formula for area of a trapezoid.
Plugging values in formula.
215 = 
(21+b2)× 13.
215 = 6.5(21+b2)
Dividing both sides by 6.5, we get
33.08 = 21+b2.
Subtracting 21 from both sides, we get
33.08-21 = 21-21+b2
b2 = 12.08.
<h3>Therefore, length of b2 is 12.08 units.</h3>
Answer:
H0: The new cancer drug increases the mean survival time by 30 days
Ha: The new cancer drug increases the mean survival time by 30 or more than 30 days.
If fail to reject H0 (the null hypothesis), the conclusion is that the new cancer drug increases the mean survival time by 30 days.
Step-by-step explanation:
The null hypothesis is a statement from a population parameter which is either rejected or accepted (fail to reject) upon testing. It is expressed using the equality sign.
The alternate hypothesis is also a statement from a population parameter which negates the null hypothesis and is accepted if the null hypothesis is rejected. It is expressed using any of the inequality signs.
The test is a two-tailed test because the alternate hypothesis is expressed using more than or equal to.
If I fail to reject H0, it means the test statistic falls within the region bounded by the critical values.
It would therefore be concluded that the new cancer drug increases the mean survival time by 30 days.
