Question

A right square pyramid has a base with sides that are 2 inches in length and a slant height of 7 inches. If the lengths of the sides of the base and the slant height are multiplied by 7, by what factor is the surface area multiplied? A. 7 B. 14 C. 28 D. 49

Answer 1

Answer:

Step-by-step explanation:

base b = 2 in

slant height L = 7 in

lateral area = 4·½bL = 4·½·2·7 = 28 in²

base area = b² = 4 in²

surface area = 28+4 = 32 in²

If b = 14 and L = 49:

lateral area = 4·½·14·49 = 1372 in²

base area =  196 in²,

and surface area = 1372+196 = 1568 in²

The surface area has multiplied by 49.

Answer 2

Answer:

49

Step-by-step explanation:

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